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3 years ago

Please answer for a and b

Mathematics

2 answers:

xz_007 [3.2K]3 years ago

7 0

Answer:

Step-by-step explanation:

a can't be an integer

8/√2 doesn't reduce to an integer. It will give you 4*√2 * √2/√2 = 4√2

-√18/√2 = -√(3*3*2)/√2 = -3(√2)/√2 = -3

At best you will get 4√2 - 3

a = 4√2

b = - 3

Edit

b is correct. the answer for b = -3

a can't be done giving an integer answer. My best guess is 4 but that is not the correct answer. You could write it as (4 - 3)√2

My advice to you is to present it to your instructor and see what he/she comes up with.

Furkat [3]3 years ago

4 0

Answer:

Step-by-step explanation:

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What is the solution to the equation 4x + 2(x − 2) = 4x + x − 12? (1 point)

Anettt [7]

Answer:

It's -8

Step-by-step explanation:

DISTRIBUTE :

4x + 2( x - 2 ) = 4x + x - 12

4x + 2x - 4 = 4x + x - 12

COMBINE LIKE TERMS :

4x + 2x - 4 = 4x + x - 12

6x - 4 = 4x + x - 12

COMBINE LIKE TERMS :

6x - 4 = 4x + x - 12

6x - 4 = 5x - 12

ADD 4 TO BOTH SIDES :

6x - 4 = 5x - 12

6x - 4 + 4 = 5x - 12 + 4

ADD THE NUMBERS/ SIMPLIFY :

6x = 5x - 8

SUBTRACT 5x FROM BOTH SIDES :

6x = 5x - 8

6x - 5x = 5x - 8 - 5x

SIMPLIFY :

x = -8

3 0

3 years ago

PLZ HELP THIS IS TIMED!!!!

mihalych1998 [28]

Answer:

For the sequence is $-\frac{2}{3}$ ,-4 ,-24 ,-144 ,...

Hence the formula $f(x)=-\frac{2}{3}(6)^{x-1}$ for x=1,2,3,... represents the given geometric sequence

Step-by-step explanation:

Given sequence is $-\frac{2}{3}$ ,-4 ,-24 ,-144 ,...

To find the formula to describe the given sequence :

Let $a_1=\frac{-2}{3}$ , $a_2=-4$ , $a_3=-24$ ,...

First find the common ratio

$r=\frac{a_2}{a_1}$ here $a_1=\frac{-2}{3}$ and, $a_2=-4$

$=\frac{-4}{\frac{-2}{3}}$

$=\frac{4\times 3}{2}$

$=\frac{12}{2}$

$r=6$

$r=\frac{a_3}{a_2}$ here $a_2=-4$ and $a_3=-24$

$=\frac{-24}{-4}$

$=6$

$r=6$

Therefore the common ratio is 6

Therefore the given sequence is geometric sequence

The nth term of the geometric sequence is

$a_n=a_1r^{n-1}$

The formula which describes the given geometric sequence is

$f(x)=a_1r^{x-1}$ for x=1,2,3,...

$=\frac{-2}{3}6^{x-1}$ for x=1,2,3,...

Now verify that $f(x)=a_1r^{x-1}$ for x=1,2,3,... represents the given geometric sequence or not

put x=1 and the value of $a_1$ in $f(x)=a_1r^{x-1}$ for x=1,2,3,...

we get $f(1)=-\frac{2}{3}(6)^{1-1}$

$=-\frac{2}{3}(6)^0$

$=-\frac{2}{3}$

Therefore $f(1)=-\frac{2}{3}$

put x=2 we get $f(2)=-\frac{2}{3}(6)^{2-1}$

$=-\frac{2}{3}(6)^1$

$=-\frac{12}{3}$

Therefore $f(2)=-4$

put x=3 we get $f(3)=-\frac{2}{3}(6)^{3-1}$

$=-\frac{2}{3}(6)^2$

$=-\frac{2(36)}{3}$

Therefore $f(3)=-24$

Therefore the sequence is f(1),f(2),f(3),...

Therefore the sequence is $-\frac{2}{3}$ ,-4 ,-24 ,-144 ,...

Hence the formula $f(x)=a_1r^{x-1}$ for x=1,2,3,... represents the given geometric sequence is verified

Therefore the formula $f(x)=-\frac{2}{3}(6)^{x-1}$ for x=1,2,3,... represents the given geometric sequence

7 0

4 years ago

Read 2 more answers

Please help me i am lost

jonny [76]

I believe the answer would be quadrant 4. Because as of right now, the triangle FGH is located in quadrant one and if rotated 360° then will move 3 quadrants counterclockwise.

7 0

3 years ago

Solve each system by elimination <br> -4x+y=-10<br> 6x-y=16

miss Akunina [59]

The y variable in both equations are opposites. So, we can add the two systems together to eliminate y and solve for x.

-4x + y = -10

6x - y = 16

2x = 6

2 × 3 = 6.

x = 3. Now we have to solve for y. Let's use 6x - y = 16.

6(3) - y = 16

18 - y = 16

18 - 2 = 16, so y = 2.

x = 3

y = 2.

Or if you have to put it in coordinate form: (3, 2)

3 0

3 years ago

Please help me and I’ll give you brainiest!!!!!!!!! :)<br><br> Thanks!!!????!!!!

Maksim231197 [3]

Answer:

multiple y and get through the point

8 0

3 years ago