1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
balandron [24]
3 years ago
10

Two ropes are attached to the bumper of a car. Rope A is pulled with a force of 60 pounds at an angle of 30° to the horizontal g

round, and rope B is pulled with a force of 80 pounds at an angle of 15° to the horizontal ground. The same effect can be produced by a single rope pulling with what force and at what angle to the ground?
Mathematics
1 answer:
lbvjy [14]3 years ago
8 0
<span>The forces caused by these two ropes could be equally produced by a single rope pulling at 138.82 pounds at an angle of 21.42 degrees to the horizontal ground. This can be found by considering each rope as the hypotenuse of a triangle. One leg of these triangles is the ground, and the other is perpendicular to the ground. Using Sine and Cosine you can find the components of the force in the horizontal and vertical directions. These are then added to find the resultant force components. The pythagorean theorem can then be used to find the net force of 138.82 pounds, and inverse tangent can be used to find the resultant angle of 21.42 degrees. *These calculations were done to two significant digits. If more precision is desired you can repeat these calculations to the desired number of significant digits.</span>
You might be interested in
Determine if each graph represent a direct proportional or not
Troyanec [42]

Answer:

i hope everyone has a good day keep your head up at all times and dont give up

Step-by-step explanation:

5 0
2 years ago
The GCF of 15 and 27 is _____.
daser333 [38]
The GCF if 3.  Please mark Brainliest!!!
3 0
3 years ago
Read 2 more answers
What is the difference between kilometers and kilograms?
Leona [35]
Kilometers is for distance, and kilograms is for solids
6 0
2 years ago
Read 2 more answers
Explain and show how to find the square root of 50 to the nearest tenth
4vir4ik [10]

Answer:

\sqrt{50}=7.1

Step-by-step explanation:

We want to find the square root of 50;

We need to first rewrite 50 as a prime factorization.

\sqrt{50}=\sqrt{25\times 2}

We now split the square root to get:

\sqrt{50}=\sqrt{25}\times \sqrt{2}

Take square root to get:

\sqrt{50}=5 \sqrt{2}

\sqrt{50}=5(1.414)=7.07

To the nearest tenth we have \sqrt{50}=7.1

7 0
3 years ago
What is 82447.96 rounded to the nearest cubic inch?
Zinaida [17]

Answer:

82448 Cubic Inches

Step-by-step explanation:

Our number is 82447.96

We know that we want to try our best to make this a whole number.

So, lets round 82447.96 up from the decimal point.

now the 0.06 will round the the 0.9 up.

Now we add the 1.0 to 82447.

Our number is now 82448.

Our number rounded to the nearest cubic inch is 82448.

<em>~CaityConcerto</em>

8 0
3 years ago
Read 2 more answers
Other questions:
  • A rectangular garden has dimensions of 100 feet by 10 feet. Next season, the garden is decreased to 2/5 of its size. How many sq
    13·1 answer
  • The total number of f orbitals in an f subshell is
    8·1 answer
  • Steven flips a coin several times to see how often heads occurs. Is this an experimental or theoretical probability?
    7·1 answer
  • Cesium-137 has a half-life of about 30 years. A) Find the annual decay rate and round final result to 4 decimal places. B) Find
    15·1 answer
  • If a doctor gives you three pills and tells you to take one pill every half hour, how long would it take before all the pills ha
    12·1 answer
  • Please help what is the answer?
    15·1 answer
  • Help with math please!!
    11·1 answer
  • HELP PLEASEEEE!!!
    12·1 answer
  • LaKeisha Jones earned $35.800 in the first year of her new job. After receiving a
    9·1 answer
  • Maths help me maths giving 10 point​
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!