A shipping company claims that 95% of packages are delivered on time. A student wants to conduct a simulation
1 answer:
The average number of packages the led to be selected in order to find a package that was not delivered on time is 2.2 option first is correct.
<h3>What is simple random sampling?</h3>With simple random sampling, each component of the population has an equal chance of being selected for the sample.
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We have:
A shipping company claims that 95% of packages are delivered on time.
From the table:
00- 04 is the package not delivered on time.
05-99 - package delivered on time.
The first simulation's third number, 31, 64, 04, is where you can locate an item that wasn't delivered on time.
The second simulation's second number, 34, 02, is the location of a late-delivered delivery.
The third simulation is equal to 96,00 - the second number, which is the location of a late package.
The second number where to find a shipment not delivered on time in the fourth simulation is 31,04
Where to find a box that wasn't delivered on time in the fifth simulation: 98, 01, second number
The average number = (3 + 2 + 2 + 2 + 2)/5
= 11/5
= 2.2
Thus, the average number of packages the led to be selected in order to find a package that was not delivered on time is 2.2 option first is correct.
Learn more about the simple random sampling here:
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Height of another tree that cast a shadow which is 20ft long is 5 feet approximately
<h3><u>Solution:</u></h3>Given that tree with a height of 4 ft casts a shadow 15ft long on the ground
Another tree that cast a shadow which is 20ft long
<em><u>To find: height of another tree</u></em>
We can solve this by setting up a ratio comparing the height of the tree to the height of the another tree and shadow of the tree to the shadow of the another tree
Let us assume,
Height of tree =
Length of shadow of tree =
Height of another tree =
Length of shadow of another tree =
Set up a proportion comparing the height of each object to the length of the shadow,
Substituting the values we get,
So the height of another tree is 5 feet approximately