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3 years ago

PLEASE HELP meeeeeeee

Mathematics

2 answers:

Firlakuza [10]3 years ago

7 0

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{4 \sqrt{15k} + 3 \sqrt{5k} }}}}}$

Option B is the correct option.

Step-by-step explanation:

$\sf{ \sqrt{15k} (4 + \sqrt{3} )}$

Distribute √ 15 k through the parentheses

$\dashrightarrow{ \sf{4 \sqrt{15k} + \sqrt{15k \times 3}}}$

$\dashrightarrow{ \sf{4 \sqrt{15k} + \sqrt{45k} }}$

$\dashrightarrow{ \sf{4 \sqrt{15k} + 3 \sqrt{5k} }}$

Hope I helped!

Best regards! :D

Morgarella [4.7K]3 years ago

5 0

Answer: B i hope this helps!

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago

The points (-3,-1) and (-3,5) are adjacent vertices of a rectangle. Two of the sides of the rectangle have a length of 8 units.

taurus [48]

Answer:

The answer to your question is 10 units

Step-by-step explanation:

Data

A (-3, -1)

B (-3 , 5)

length of a side = 8 units

Process

1.- Calculate the distance between A and B

dAB = $\sqrt{(x2 - x1)^{2} + (y2 - y1)^{2}}$

x1 = -3 y1 = -1

x2 = -3 y2 = 5

-Substitution

dAB = $\sqrt{(-3 + 3)^{2}+ (5 + 1)^{2}}$

dAB = $\sqrt{0^{2} + 6^{2}}$

dAB = $\sqrt{36}$

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2.- Calculate the diagonal using the Pythagorean theorem.

c² = a² + b²

c² = 6² + 8²

c² = 36 + 64

c² = 100

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- Conclusion

The diagonal of the rectangle measures 10 units

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3 years ago

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3 years ago

Write the general equation for the circle that passes through the points: (1, 7) (8, 6) (7, -1)

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Answer:

$x^{2} +y^{2} +(-8)\times x+ (-6)\times y = 0$

Step-by-step explanation:

General equation of circle is $x^{2} +y^{2} +2\times g \times x+2\times f\times y+c = 0$ ---------------------(1)

This circle passes through the given three points, (1,7) , (8,6) and (7,-1).

Substitute (1,7) in (1),

1 + $7^{2} +2\times g\times 1 + 2\times f\times 7 +c$ =0

2g + 14f + c = -50 -------------(2)

Substitute (8,6) in (1),

$8^{2} + 6^{2} +2\times g \times 8+2\times f\times 6 +c=0$

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Substitute (7,-1) in (1),

$7^{2} + (-1)^{2} +2\times g \times 7+2\times f\times (-1) +c=0$

14g - 2f + c = -50 ---------------(4)

Solving (2),(3) amd (4) simultaneously,

g = -4

f = -3

c = 0

Equation of circle is

$x^{2} +y^{2} +(-8)\times x+ (-6)\times y = 0$

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3 years ago

￼PLEASE HELP meeeeeeee

PLEASE HELP meeeeeeee