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Leokris [45]
2 years ago
12

30 POINTS NEED HELP ASAP MATH QUESTION A. 19 B. 108 C. 133 D. 763

Mathematics
1 answer:
Oduvanchick [21]2 years ago
3 0

Answer:

lol that's 14 points my boy

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Given right triangle jkl, what is the value of cos(l)? five-thirteenths five-twelfths twelve-thirteenths twelve-fifths
kykrilka [37]

The value of the cosine ratio cos(L) is 5/13

<h3>How to determine the cosine ratio?</h3>

The complete question is added as an attachment


Start by calculating the hypotenuse (h) using

h^2 = 5^2 + 12^2

Evaluate the exponent

h^2 = 25 + 144

Evaluate the sum

h^2 = 169

Evaluate the exponent of both sides

h = 13

The cosine ratio is then calculated as:

cos(L) = KL/h

This gives

cos(L) =5/13

Hence, the value of the cosine ratio cos(L) is 5/13

Read more about right triangles at:

brainly.com/question/2437195

#SPJ1

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1 year ago
.............................................................
Len [333]

Answer:

0.058863

Step-by-step explanation:

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