Nicole simplifies 2^a*2^5/2^b to 2^(a-b+5). Which two properties of exponents did she use while simplifying the expression?

Mathematics

1 answer:

emmainna [20.7K]3 years ago

5 0

Answer:

Step-by-step explanation:

2^a*2^5/2^b = 2^(a+5)/2^b. using power of a product property.

then

2^(a+5)/2^b= 2^(a+5)*2^-b. Using Negative Exponent property.

Again we can use power of a product property and we get 2^(a+5)*2^-b=2^(a-b+5)

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Answer:

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Step-by-step explanation:

The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be $y$ . The magnitude of $40\text{ m/s}$ will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is $60^{\circ}$ , we have:

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Now that we've found the vertical component of the velocity and launch, we can use kinematics equation $v_f^2=v_i^2+2a\Delta y$ to solve this problem, where $v_f/v_i$ is final and initial velocity, respectively, $a$ is acceleration, and $\Delta y$ is distance travelled. The only acceleration is acceleration due to gravity, which is approximately $9.8\:\mathrm{m/s^2}$ . However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.