Anyone know how to do this?
1 answer:
You might be interested in
notice that the denominator can be factored into (x-3)(x+3).
Now you can cross out (x - 3) from the numerator and denomiantor resulting in a simplified fraction of
Plug the limit value (which is 3) into the simplified fraction.
Answer:
The answer is the first option: 1) > the quantity
times
minus
all over
The explanation is shown below:
1. To solve this problem you must pply the following proccedure:
2. Move the term to the left member. As the variable is negative, multiply the expression by
and change the direction of the sign: