X-9=12
x-9+9=12+9
You need to add 9 to each side of the equation.
x=21
The second table does not represent a function
Answer:
Step-by-step explanation:
90.25$
Answer:
4Hz
Step-by-step explanation:
Standard form of a sine or cosine function,
y = acos(b(x+c))
where a is the amplitude, b is the value to find the period. and c is the phase shift.
Period = \frac{2\pi}{b}
From the equation given in the question,

We can see:
Amplitude = 3,
Period = \frac{2\pi}{8\pi} = 1 / 4
Phase Shift = 1 / 16
Now we want to find the frequency.
Frequency = 1 / Period
= 1 / (1/4)
= 4Hz
Problem 1 Answer: x = 2/3y+8
Show Work:
Step 1: Add 2y to both sides.
3x−2y+2y=24+2y
3x=2y+24
Step 2: Divide both sides by 3.
3x/3 = 2y+24/3
x = 2/3y+8
Problem 2 Answer: x=−2y+48
Show Work:
Add -2y to both sides.
x+2y+−2y=48+−2y
x=−2y+48