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3 years ago

Find the first term and the common difference of the arithmetic sequence whose 5 th term is 3 and 19 th term is 45 .

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

6 0

Where (a) is first term
and common diff is (d)

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3 years ago

Determine if the graph of y=x/x^2-4 is symmetrical with respect to the x-axis, the y-axis, or the origin.

aalyn [17]

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Answer:

c. about the origin

Step-by-step explanation:

The function is odd: replacing x with -x gives the negative of the function value:

f(-x) = -f(x)

Odd functions are symmetrical about the origin.

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3 years ago

A machine can produce a maximum of 600 parts per day. Yesterday, it produced 75 % of its maximum capacity. How many parts did th

gizmo_the_mogwai [7]

Answer:

450

Step-by-step explanation:

here is a fast way:

1- 75% = 75/100 = 3/4

2- 600 × (3/4) = 450

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3 years ago

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Omar's credit card has an APR of 26% calculated on the previous monthly

wariber [46]

Answer:

B. $257.33

Step-by-step explanation:

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4 0

3 years ago

If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?

eduard

Answer:

$cos(\alpha+\beta)=-\frac{84}{85}$

Step-by-step explanation:

we know that

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

Remember the identity

$cos^{2} (x)+sin^2(x)=1$

step 1

Find the value of $sin(\alpha)$

we have that

The angle alpha lie on the III Quadrant

The values of sine and cosine are negative

$cos(\alpha)=-\frac{8}{17}$

Find the value of sine

$cos^{2} (\alpha)+sin^2(\alpha)=1$

substitute

$(-\frac{8}{17})^{2}+sin^2(\alpha)=1$

$sin^2(\alpha)=1-\frac{64}{289}$

$sin^2(\alpha)=\frac{225}{289}$

$sin(\alpha)=-\frac{15}{17}$

step 2

Find the value of $cos(\beta)$

we have that

The angle beta lie on the IV Quadrant

The value of the cosine is positive and the value of the sine is negative

$sin(\beta)=-\frac{4}{5}$

Find the value of cosine

$cos^{2} (\beta)+sin^2(\beta)=1$

substitute

$(-\frac{4}{5})^{2}+cos^2(\beta)=1$

$cos^2(\beta)=1-\frac{16}{25}$

$cos^2(\beta)=\frac{9}{25}$

$cos(\beta)=\frac{3}{5}$

step 3

Find cos⁡ (α + β)

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

we have

$cos(\alpha)=-\frac{8}{17}$

$sin(\alpha)=-\frac{15}{17}$

$sin(\beta)=-\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute

$cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})$

$cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}$

$cos(\alpha+\beta)=-\frac{84}{85}$

4 0

3 years ago