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3 years ago

What are some tools you could select to measure length?Explain when you would use them.

Mathematics

2 answers:

Otrada [13]3 years ago

5 0

I would use a ruler or something to make a perfect circle

ZanzabumX [31]3 years ago

4 0

Answer:

I would use a ruler or something to make a perfect circle

Step-by-step explanation:

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What is Point slope form

OLEGan [10]

Answer:

y- y1 = m(x-x1)

Note: Where m is the slope and (x1, y1) is any point on the line

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4 years ago

Two vertical poles of heights 60 ft and 80 ft stand on level ground, with their bases 100 ft apart. A cable that is stretched fr

Andreyy89

Answer:

Step-by-step explanation:

Given

height of two Poles are 60 and 80 ft

Distance between them is 100 ft

Let x be the distance of Pole of ht 80 ft from Point of stretch

thus length of rope is given by

$L=L_1+L_2$

$L_1=\sqrt{80^2+x^2}$

$L_2=\sqrt{60^2+(100-x)^2}$

$L=\sqrt{80^2+x^2}+\sqrt{60^2+(100-x)^2}$

differentiate w.r.t x we get

$\frac{\mathrm{d} L}{\mathrm{d} x}=\frac{2x}{2\sqrt{80^2+x^2}}-\frac{2\left ( 100-x\right )}{\sqrt{60^2+\left ( 100-2x\right )^2}}$

Put $\frac{\mathrm{d} L}{\mathrm{d} x}=0$ to get minimum value

$\frac{2x}{2\sqrt{80^2+x^2}}=\frac{2\left ( 100-x\right )}{\sqrt{60^2+\left ( 100-2x\right )^2}}$

squaring

$x^2\left ( (100-x)^2+60^2\right )=(100-x)^2(80^2+x^2)$

Rearranging

$28x^2-1800x+640000=0$

$x=\frac{400}{7}$

thus $L_1=98.312 ft$

$L_2=73.73 ft$

$L=172.04 ft$

7 0

3 years ago

B) Describe fully the single transformation that maps triangle B onto triangle C. (2) <br>

andrey2020 [161]

Answer: Reflection over the x-axis

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2 years ago

I'm giving out free point if you know this 10+7 it easy

Galina-37 [17]

The awnser would be 17:)

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3 years ago

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Robert needs to cut four shelves from a board that is 2.5 meters long. The second shelf is 18 centimeters longer than twice the

jeyben [28]

I would say 640.5 centimeters. However, remember that this is high school work, and I am only in middle school. This may not be correct, as I am doubting myself, yet cannot find errors in my work. Please take caution with this answer! Hope this isn't a detriment to you, bye! :)

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3 years ago

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