Answer:
This is not true
Explanation:
The optimal Huffman code is used to encrypt and compress text files. It uses fixed-length code or variable-length code for encryption and compression of data.
The professor's character code is similar to Huffman's variable-length coding which uses variable length od binary digits to represent the word strings. The file size of the text file above is;
= 6 x 1 + 2 x 2 + 3 x 2 + 2 x 2 + 8 x 1 = 28 bits
This would be the same for both cases.
The encrypt would be the problem as the encoded and decoding of the characters B and E may cause an error.
I don't think so because the old computers may have not been to date as what we have now but check it out and see.
The relational operator used would probably be <=
Answer:
#part 1
#read the amount
amount=int(input("enter the amount:"))
#find the dollars
doll=int(amount/100)
// find the cents
cent=amount%100
#print output
print("{} dollars and {} cents.".format(doll,cent))
#part 2
#read a floating point
temperature=float(input("enter the temperature:"))
#part 3
#read a word
firstWord=input("enter a word:")
Explanation:
In part 1, read amount and the find the dollars with the help of "/" operator. Then find the cents with "%" operator and print both.In part 2, read a point and cast it to float then assign it to variable "temperature".In part 3,Read a word and assign it to variable "firstWord".
Output:
enter the amount:4321
43 dollars and 21 cents.
enter the temperature:12.5
enter a word:hello
