Answer:
This is because the other person has "Focus Mode" turned on. When this is turned on, all of your messages that you send to him/her will be silenced.
Answer:
The correct answer to the following question will be "False".
Explanation:
- Web crawlers make copies of google search recovery pages that index the streamed pages to allow subscribers to more effectively search. It collects details of Web pages in an automatically generated or semi-automated form.
- The code of HTML and Hyperlink can be checked by crawlers. They could be used for scraping of the web.
Therefore, the given statement is false.
Answer in python:
import random
money = 10
winnings = 0
def main():
global winnings
global money
dice_num = random.randrange(1,6)
input_str = "Guess the dice number. You have $"+str(money)+" > "
input_num = input(input_str)
if int(input_num) == dice_num:
money = money + 10
winnings = winnings + 10
else:
money = money - 1
if money < 0:
print("You lose. You won "+str(winnings)+" times. Press enter to try again")
useless_variable = input()
main()
else:
main()
main()
Explanation:
Answer:
- public static String bothStart(String text1, String text2){
- String s = "";
-
- if(text1.length() > text2.length()) {
- for (int i = 0; i < text2.length(); i++) {
- if (text1.charAt(i) == text2.charAt(i)) {
- s += text1.charAt(i);
- }else{
- break;
- }
- }
- return s;
- }else{
- for (int i = 0; i < text1.length(); i++) {
- if (text1.charAt(i) == text2.charAt(i)) {
- s += text1.charAt(i);
- }else{
- break;
- }
- }
- return s;
- }
- }
Explanation:
Let's start with creating a static method <em>bothStart()</em> with two String type parameters, <em>text1 </em>&<em> text2</em> (Line 1).
<em />
Create a String type variable, <em>s,</em> which will hold the value of the longest substring that both inputs start with the same character (Line 2).
There are two possible situation here: either <em>text1 </em>longer than<em> text2 </em>or vice versa. Hence, we need to create if-else statements to handle these two position conditions (Line 4 & Line 13).
If the length of<em> text1</em> is longer than <em>text2</em>, the for-loop should only traverse both of strings up to the length of the <em>text2 </em>(Line 5). Within the for-loop, we can use<em> charAt()</em> method to extract individual character from the<em> text1</em> & <em>text2 </em>and compare with each other (Line 15). If they are matched, the character should be joined with the string s (Line 16). If not, break the loop.
The program logic from (Line 14 - 20) is similar to the code segment above (Line 4 -12) except for-loop traverse up to the length of <em>text1 .</em>
<em />
At the end, return the s as output (Line 21).
Answer:(c) abstract class A { abstract void unfinished(); }
Explanation:
A legal abstract class must have the keyword abstract before the class and an abstract class has abstract functions with the keyword abstract written and a void as the return type.
