What’s the prime factorization of 650

Mathematics

2 answers:

Arturiano [62]3 years ago

4 0

The exponents in the prime factorization are, 1, 2, and 1.

tatyana61 [14]3 years ago

3 0

2 • 52 • 13, 650 is not a prime number.

Prime Factors of 650 =2, 5, 5, 13

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A computer programmer has a 35 chance of finding a bug in any given program. what is the probability that she finds a bug within

vlada-n [284]

Answer:

Answer is d

Step-by-step explanation:

A computer programmer has a 35 change of finding a bug in any given program.
we have to find probability that she finds a bug within the first 3 programs she examines
success = 0.35, failure = 0.65
She get a bug in the first program itself
p = 0.35
She get a bug in 2nd program
q = 0.65×0.35 =0.2275
She get a bug in the 3rd program
r = 0.65×0.65×0.35
r = 0.147875
Add all the three probabilities for answer
P = p+q+r
P = 0.35+0.2275+0.147875
P = 0.725375
P = 0.73
The probability of the answer is 0.73

7 0

3 years ago

Help me with this problem please right away

svlad2 [7]

Answer:

$6\frac{1}{2} = A$

Step-by-step explanation:

The first step is to use the Distance Formula to figure out the lengths of the two legs:

$\sqrt{[-x_1 + x_2]^{2} + [-y_1 + y_2]^{2}} = D$

R(1, 1) and P(−1, −2) ↷

$\sqrt{[1 + 1]^{2} + [2 + 1]^{2}} = \sqrt{2^{2} + 3^{2}} = \sqrt{4 + 9} = \sqrt{13}\\ \\ \sqrt{13} = RP$

Q(2, −4) and P(−1, −2) ↷

$\sqrt{[1 + 2]^{2} + [2 - 4]^{2}} = \sqrt{[-2]^{2} + 3^{2}} = \sqrt{4 + 9} = \sqrt{13} \\ \\ \sqrt{13} = QP$

* So, by my calculations, we have an isosceles right triangle, and according to the 45°-45°-90° triangle theorem, we automatically know that the hypotenuse, RQ, is $\sqrt{26}$ :

30°-60°-90° triangle theorem

2x, x, x√3

↑ ↑ ↑

h leg leg

45°-45°-90° triangle theorem

x√2, x, x

↑ ↑ ↑

h legs

So now, we have to find the area of the triangle by taking half of either height or base, then multiplying that by the height or base, but since this is an isosceles right triangle, it does not matter:

$[\frac{h}{2}][b] = A \: \:OR\: \: [\frac{b}{2}][h] = A \: \:OR \: \: \frac{hb}{2} = A$