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Ket [755]
3 years ago
8

a child lifts a 5.0-newton toy to a height of 0.50 meters. how much work is done on the toy? 0.0 j 2.5 j 4.5 j 10 j

Mathematics
2 answers:
natta225 [31]3 years ago
8 0
Since work = force * distance, the answer would 5*.5, which is 2.5 J
gogolik [260]3 years ago
7 0

Answer:

option B. 2.55 j.

Step-by-step explanation:

A child lifts a 5 newton toy to a height of 0.50 meters.

We have to calculate the work done on the toy.

Since we know    work done = Force × Displacement

                                                = 5 × 0.50

                                                = 2.55 j

Therefore, answer will be option B. 2.55 j.

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A gift box has dimensions of: 8 1 2 inches, 5 1 2 inches, and 2 1 2 inches, respectively. how many cubes with side lengths of 1
Mariulka [41]
Number of 1/2-inch cubes length-wise = 8 1/2 ÷ 1/2 = 17
Number of 1/2-inch cubes width-wise = 5 1/2 ÷ 1/2 = 11
Number of 1/2-inch cubes height-wise = 2 1/2 ÷ 1/2 = 5

Number of 1/2-inch cubes = 17 x 11 x 5 = 935

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Answer: 935 1/2-inch cubes are needed.
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3 years ago
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Step-by-step explanation:

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8 0
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Step-by-step explanation:

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