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3 years ago

Help a brother out with this math shi

Mathematics

1 answer:

liraira [26]3 years ago

6 0

(7^13)^3 * 7^0

= 7^(13 * 3) * 1

= 7^39

Answer

7^39

P.S. Any number (except 0) to the 0 exponent is equal to 1

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Gabby's scores on her first 4 math test where 87, 92, 76 and 89. What is the minimum score Gabby needs to make on the 5th test

Ganezh [65]

She would need to make an 89 on her last test. I hope this helped ^^

What I did is I put a made a list in ascending order (Least to greatest). Next, I added a number starting from 80 and then counted up. I added every number together and divided it by 5 every time I changed the number. Finally I got to the number 89 and it totaled to be 85.

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3 years ago

Find the solution set for the inequality x-10<10

Lelu [443]

Answer:

x<20

Step-by-step explanation:

x-10<10

add 10 to both sides

x<20

X can therefore be anything less than 20.

4 0

2 years ago

Please help quickly im on a test<br> if f(x)=x+4, and g(x)=2x+4, what is f(2)+g(2)?

JulsSmile [24]

Answer:

Step-by-step explanation:

f(2)+g(2)

(2+4)+(2×2+4)

6+8

5 0

2 years ago

A man invests $2000 in an account that pays 6.5% interest per year, compounded quarterly.

skelet666 [1.2K]

Answer:

The correct answer is a. $2275.28; b. 17.04 years

Step-by-step explanation:

Principal to be invested is $2000

Interest rate (r) per year is 6.5 quarterly.

Interest is calculated compoundly.

a. Time (t) for the investment is given to be 2 years.

Amount after two years is = Principal × $( 1+ \frac{r}{100n}) ^ {nt}$ where the value of n is 4.

⇒ A = 2000 × $( 1+ \frac{6.5}{400}) ^ {8}$

⇒ A = $2275.28.

b. Now the value of A is given to be triple the principal = $ (3 × 2000).

Therefore we need to find the value of t.

⇒ 3 × 2000 = 2000 × $( 1+ \frac{6.5}{400}) ^ {4t}$

⇒ ㏑ 3 = 4t × ㏑ ( 1.01625)

⇒ t = 17.04

Therefore it would take 17.04 years for the principal to triple.

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3 years ago

Please answer it now in two minutes

o-na [289]

Answer:

p = 3

Step-by-step explanation:

This is an isosceles right triangle

=> 2side^2 = (hypotenuse)^2

=> 2p^2 = (3sqrt(2))^2

=> 2p^2 = 18

=> p^2 = 9

=> p = 3

5 0

3 years ago