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tensa zangetsu [6.8K]
3 years ago
12

A right triangle kin the coordinate plane has vertices at (0,0), (0,8)c, and (6,0). The triangle is rotated 90° counter clockwis

e about the origin. What are the coordinates of the rotated triangle

Mathematics
1 answer:
KatRina [158]3 years ago
6 0

Answer:

C

Step-by-step explanation:

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To convert a distance of 12000 feet to miles which ratio could you multiply by?
Luba_88 [7]

Answer:

2.28 miles

Step-by-step explanation:

1 foot = 0.00019miles

12000 feet = x miles

Cross multiply

x = 12000 x 0.00019

x = 2.28 miles

5 0
3 years ago
The length (L) of a rectangle of fixed area varies inversely as the width (W).
Andreyy89

Answer:

6.25

Step-by-step explanation:

If 10ft=8ft

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cross multiply

5 0
2 years ago
PLEASE HELP ASAP 35 POINTS
podryga [215]

Your answer is A

It cannot be C because the line y > -2  uses the (>) greater than symbol.

When equations have a greater than symbol, they are graphed using a <u>dotted line. </u>

It cannot be D because the line is  y ≤ - l x-1 l

with the less than or equal to sign (≤) , you use a <u>solid line</u> to graph


With the<u> greater than</u> symbol for y > -2 , the shaded region must be <em>above </em>this line.

With the <em>less than </em>or equal to sign in y ≤ - l x-1 l , the shaded region must be <em>below </em>the line.


Hope I helped - message me if you have any questions :)

5 0
3 years ago
Find all points having an x-coordinate of 2 whose distance from the point (-1,-2) is 5
xxTIMURxx [149]
d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\&#10;5=\sqrt{(-1-2)^2+(-2-y_1)^2}\\&#10;\sqrt{9+4+4y_1+y_1^2}=5\\&#10;y_1^2+4y_1+13=25\\&#10;y_1^2+4y_1-12=0\\&#10;y_1^2+6y_1-2y_1-12=0\\&#10;y_1(y_1+6)-2(y_1+6)=0\\&#10;(y_1-2)(y_1+6)=0\\&#10;y_1=2 \vee y_1=-6\\\\&#10;\boxed{(2,2),(-6,2)}&#10;&#10;
3 0
3 years ago
How do I find the missing sides of this triangle by using trigonometry
Lemur [1.5K]

Step-by-step explanation:

Use SOH-CAH-TOA.

Sine = Opposite / Hypotenuse

Cosine = Adjacent / Hypotenuse

Tangent = Opposite / Adjacent

You're given an angle, the adjacent side to that angle, and the hypotenuse.  So use cosine.

Cosine = Adjacent / Hypotenuse

cos 37° = 48 / x

Multiply both sides by x.

x cos 37° = 48

Divide both sides by cos 37°.

x = 48 / cos 37°

If desired, use a calculator to evaluate.

x ≈ 60.1

8 0
3 years ago
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