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Mashutka [201]
4 years ago
14

A local​ eat-in pizza restaurant wants to investigate the possibility of starting to deliver pizzas. The owner of the store has

determined that home delivery will be successful if the average time spent on the deliveries does not exceed 3434 minutes. The owner has randomly selected 1818 customers and has delivered pizzas to their homes in order to test if the mean delivery time actually exceeds 3434 minutes. Suppose the​ P-value for the test was found to be 0.0281281. State the correct conclusion.
Mathematics
1 answer:
gavmur [86]4 years ago
6 0

Answer:

Step-by-step explanation:

The owner of the store has determined that home delivery will be successful if the average time spent on the deliveries does not exceed 34 minutes. This is the null hypothesis. It is written as

H0 : µ ≤ 34

The alternative hypothesis would be

Ha : µ > 34

This is a right tailed test because of the greater then symbol in the alternative hypothesis. Since the p value for the test was found to be 0.0281281, if we use a significant level of 0.05, then the conclusion would be

Reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the average time spent on the deliveries does exceed 34 minutes.

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Answer:

240 cm², A = 300 cm², and 540 cm²

Step-by-step explanation:

1) The area of a parallelogram is A = bh, so:

A = (20)(12)

A = 240 cm²

2) Similarly, the area of a rectangle is A = bh, so:

A = (15)(20)

A = 300 cm²

3) The composite area is the sum of both the rectangle's area and the parallelogram's area, so:

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Kendra bought 4 boxes of doughnuts. There were 6 doughnuts in each box. She divided the doughnuts equally among 8 people. How ma
Zarrin [17]
Well this is pretty easy.
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First reason: Definition of supplementary

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Step-by-step explanation:

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Researchers have noted a decline in cognitive functioning as people age (Bartus, 1990). However, the results from other research
kolbaska11 [484]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

Yes the researcher can  conclude that the supplement has a significant effect on cognitive skill

b

d =  0.5778

c

The result of this hypothesis test shows that there is sufficient evidence to  that the supplement had significant effect.The measure of effect size is  large due to the large value of Cohen's d (0.5778 > 0.30 )

Step-by-step explanation:

From the question we are told that

  The sample size is  n=16

    The sample mean is  M  =  50.2

    The standard deviation is \sigma  = 9

    The  population mean is  \mu =  45

     The level of significance is  \alpha =  0.05

The null hypothesis is H_o  \mu =45

The alternative hypothesis is H_a  \mu \ne 45

Generally the test statistics is mathematically represented as

          z =  \frac{M -  \mu}{\frac{\sigma}{\sqrt{n} } }

=>       z =  \frac{50.2 - 45}{\frac{9}{\sqrt{16} } }

=>       z =  2.31

Generally the p-value is mathematically represented as

     p-value  =  2 *  P(Z >  z )

      p-value  =  2 *  P(Z >  2.31 )

From the z-table  

      P(Z >  2.31 ) = 0.010444

=>     p-value  =  2 *  0.010444

=>     p-value  =  0.021

From the obtained values we see that p-value <  0.05

 Decision Rule

 Reject the null hypothesis

Conclusion

There is sufficient evidence to conclude that the supplement has a significant effect on the cognitive skill of elderly adults

Generally the Cohen's d for this study is mathematically represented as

    d =  \frac{M  -  \mu}{\sigma }

=>  d =  \frac{50.2 -45}{9 }

=>  d =  0.5778

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Effectus [21]

Step-byp explanation:

x is the answer

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