Write an equation of the line passing through (2,4) and (3,5). Give the answer in standard form.

A train left for Houston, and 7 hours later, a car traveling 62 mph tried catching up to the train. After 4 hours, the car caugh

lana [24]

Answer: 22.55 mph

Step-by-step explanation:

Let the speed of the train be n

4 × 62 = 248 which is the distance travelled by the car in 4 hours and the train travelled in 11 hours

11 × n = 248

11n = 248

n = 248/11

n = 22.55mph

5 0

4 years ago

Can someone please help me solve this?

aleksklad [387]

Answer:

centre = (-5, -4)

radius = 7.42

Step-by-step explanation:

The general form for center-radius is

(x - h)² + (y - k)²= r²

Center = (h, k)

Radius = r

Rearrange the equation.

(x² + 10x) + (y² + 8y) - 14 = 0

Add 14 on both sides.

(x² + 10x) + (y² + 8y) = 14

(10/2)² = 25

(8/2)² = 16

Add 25 and 16 to both sides.

(x² + 10x + 25) + (y² + 8y + 16) = 14 + 25 + 16

Factor left side of the equation.

(x+5)² + (x+4)² = 55

(55) = (7.416198)²

(x+5)² + (x+4)² = 7.42²

The radius is 7.42.

The centre is at (-5, -4).

8 0

3 years ago

Read 2 more answers

The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm. The area of printed material on the po

grin007 [14]

Answer:

Dimensions of printed poster are

length is 32 cm

width is 48 cm

Step-by-step explanation:

Let's assume

length of printed poster is x cm

width of printed poster is y cm

now, we can find area of printed poster

so, area of printed poster is

$=xy$

we are given that area as 1536

so, we can set it to 1536

$xy=1536$

now, we can solve for y

$y=\frac{1536}{x}$

now, we are given

The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm

so, total area of poster is

$A=(8+x+8)\times (12+y+12)$

$A=(x+16)\times (y+24)$

now, we can plug back y

$A=(x+16)\times (\frac{1536}{x}+24)$

now, we have to minimize A

so, we will find derivative

$A'=\frac{d}{dx}\left(\left(x+16\right)\left(\frac{1536}{x}+24\right)\right)$

we can use product rule

$A'=\frac{d}{dx}\left(x+16\right)\left(\frac{1536}{x}+24\right)+\frac{d}{dx}\left(\frac{1536}{x}+24\right)\left(x+16\right)$

$=\frac{d}{dx}\left(x+16\right)\left(\frac{1536}{x}+24\right)+\frac{d}{dx}\left(\frac{1536}{x}+24\right)\left(x+16\right)$

now, we can simplify it

$A'=-\frac{24576}{x^2}+24$

now, we can set it to 0

and then we can solve for x

$A'=-\frac{24576}{x^2}+24=0$

$-\frac{24576}{x^2}x^2+24x^2=0\cdot \:x^2$

$-24576+24x^2=0$

$x=32,\:x=-32$

Since, x is dimension

and dimension can never be negative

so, we will only consider positive value

$x=32$

now, we can solve for y

$y=\frac{1536}{32}$

$y=48$

so, dimensions of printed poster are

length is 32 cm

width is 48 cm

5 0

3 years ago

Drag each interval to a box to show if the function shown is increasing, decreasing or neither over that interval

Stolb23 [73]

Answer:

6 < x < 8 is decreasing

10 < x < 14 is neither

8 < x < 10 is increasing

4 < x < 6 is increasing

1 < x < 4 is decreasing

Step-by-step explanation:

just see where the line is going up or down

down is decreasing

up is increasing

6 0

3 years ago

What is 3.8 as a fraction

slava [35]

Fraction 19/5
mixed fraction 3 4/5

8 0

4 years ago

Read 2 more answers

Write an equation of the line passing through ​(2​,4​) and ​(3​,5). Give the answer in standard form.

Write an equation of the line passing through (2,4) and (3,5). Give the answer in standard form.