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Illusion [34]
3 years ago
5

A single microvillus is a rod-like structure that is 1.0 μm in height. It has a hemispherical top approximately 0.1 μm in diamet

er. Calculate the surface area of the cylinder that forms the "sides" of the microvillus rod. Use 3.14 for π.
Mathematics
1 answer:
gregori [183]3 years ago
3 0

Answer:

so, the figure here is a cylinder with a semi sphere on the top, we know the height of whole structure, and the radius of the semi sphere, which is the same as the radius of the cylinder (you can see it because the radius of the semisphere is constant, and you can thin on it as half a sphere over a cylinder).

First, the cylinder will be the structure without the semi sphere, so his height will be te total height minus the radius of the semi sphere, which is 0.9μm.

so now we know the height and the radius of the cylinder, the surface or the sides of it is 2*3.14*r*h = 2*3.14*0.9μm*0.1μm = 0.5662μm^{2}.

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A teacher has found that the probability that a student studies for a test is 0.610.61​, and the probability that a student gets
Ann [662]

Answer with step-by-step explanation:

Let

A=Student studies for a test

B=Student gets good grade on a test

The probability that a student studies  for  a test=P(A)=0.61

The probability that a student gets   a good grade on a test=P(B)=0.79

The probability that both occur=P(A\cap B)=0.56

a.We have to find the events are independent

We know that if two events A and B are independent then

P(A)\cdot P(B)=P(A\cap B)

P(A)\cdot P(B)=0.61\times 0.79=0.4819

P(A\cap B)\neq P(A)\cdot P(B)

Hence, given events are not independent.

b.We have to find P(B/A)

P(B/A)=\frac{P(A\cap B)}{P(A)}

P(B/A)=\frac{0.56}{0.61}=0.92

c. We have to find P(A/B)

P(A/B)=\frac{P(A\cap B}{P(B)}

P(A/B)=\frac{0.56}{0.79}=0.71

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