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Illusion [34]
3 years ago
5

A single microvillus is a rod-like structure that is 1.0 μm in height. It has a hemispherical top approximately 0.1 μm in diamet

er. Calculate the surface area of the cylinder that forms the "sides" of the microvillus rod. Use 3.14 for π.
Mathematics
1 answer:
gregori [183]3 years ago
3 0

Answer:

so, the figure here is a cylinder with a semi sphere on the top, we know the height of whole structure, and the radius of the semi sphere, which is the same as the radius of the cylinder (you can see it because the radius of the semisphere is constant, and you can thin on it as half a sphere over a cylinder).

First, the cylinder will be the structure without the semi sphere, so his height will be te total height minus the radius of the semi sphere, which is 0.9μm.

so now we know the height and the radius of the cylinder, the surface or the sides of it is 2*3.14*r*h = 2*3.14*0.9μm*0.1μm = 0.5662μm^{2}.

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The graph y=e^x is transformed as shown in the graph blow which equation represents the transformed function ?
Ymorist [56]

Answer:

y=e^x+3

Step-by-step explanation:

y=e^x will go through (0,1). Since it goes through (0,4), then the function moves up 3 units. So we need to add 3 after e^x

4 0
3 years ago
3.5+2=2x-10help me HELP ME JIGGABOOS
Genrish500 [490]
3.5 + 2 = 2x - 10
5.5 = 2x -10
+10 +10
—————————
15.5 = 2x
—— ——
2 2

7.75 = x

7.75 is the answer
5 0
1 year ago
What is the measure of x?
MA_775_DIABLO [31]

when running a line, in a right-triangle, from the 90° angle perpendicular to its opposite side, we will end up with three similar triangles, one Small, one Medium and a containing Large one, from where we can use proportions to get their sides, so Check the picture below.

4 0
2 years ago
A factory worker productivity is normally distributed. one worker produces an average of 75 units per day with a standard deviat
Angelina_Jolie [31]
Let Xi be the random variable representing the number of units the first worker produces in day i.
Define X = X1 + X2 + X3 + X4 + X5 as the random variable representing the number of units the
first worker produces during the entire week. It is easy to prove that X is normally distributed with mean µx = 5·75 = 375 and standard deviation σx = 20√5.
Similarly, define random variables Y1, Y2,...,Y5 representing the number of units produces by
the second worker during each of the five days and define Y = Y1 + Y2 + Y3 + Y4 + Y5. Again, Y is normally distributed with mean µy = 5·65 = 325 and standard deviation σy = 25√5. Of course, we assume that X and Y are independent. The problem asks for P(X > Y ) or in other words for P(X −Y > 0). It is a quite surprising fact that the random variable U = X−Y , the difference between X and Y , is also normally distributed with mean µU = µx−µy = 375−325 = 50 and standard deviation σU, where σ2 U = σ2 x+σ2 y = 400·5+625·5 = 1025·5 = 5125. It follows that σU = √5125. A reference to the above fact can be found online at http://mathworld.wolfram.com/NormalDifferenceDistribution.html.
Now everything reduces to finding P(U > 0) P(U > 0) = P(U −50 √5125 > − 50 √5125)≈ P(Z > −0.69843) ≈ 0.757546   .
5 0
3 years ago
you deposit $700 in an account with an annual interest rate of 4%. calculate the amount of money you will have in that account a
vlabodo [156]

Answer:1872

Step-by-step explanation:

7 0
3 years ago
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