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erik [133]
3 years ago
5

(-10y2– 13u) – 12y² Your answer should be in simplest terms.

Mathematics
1 answer:
ASHA 777 [7]3 years ago
6 0

Step-by-step explanation:

−10y2−13u−12y2

=−10y2+−13u+−12y2

=−10y2+−13u+−12y2

=(−10y2+−12y2)+(−13u)

=−22y2+−13u answer

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What is the slope of the line passing through the point 2 comma negative 1 and the origin?
NARA [144]

Answer:

- 1/2 or - 1.5

Step-by-step explanation:

I would suggest using a table

x       y

2      -1

0      0

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from 2 to 0, u subtract 2

so y/x

1/-2

Your slope will be -1/2 or -1.5

Hope this helped!

3 0
3 years ago
For the pair of points find the distance between them and the midpoint of the line segment joining them.(720,50), (125,18)The di
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Given two points

(x_1,y_1)

and

(x_2,y_2)

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D=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}

The points given are (Sqrt(20), Sqrt(50)) and (Sqrt(125), Sqrt(8)), so their distance is >>>

\begin{gathered} D=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2} \\ D=\sqrt[]{(\sqrt[]{8}-\sqrt[]{50})^2+(\sqrt[]{125}-\sqrt[]{20})^2} \\ D=\sqrt[]{(\sqrt8)^2-2(\sqrt[]{8})(\sqrt[]{50})+(\sqrt[]{50})^2^{}+(\sqrt[]{125})^2-2(\sqrt[]{125})(\sqrt[]{20})+(\sqrt[]{20})^2} \\ D=\sqrt[]{8-2(2\sqrt[]{2})(5\sqrt[]{2})+50+125-2(5\sqrt[]{5})(2\sqrt[]{5})+20} \\ D=\sqrt[]{8-40+50+125-100+20} \\ D=\sqrt[]{63} \\ D=3\sqrt[]{7} \end{gathered}

----------------------------------------------------------------------------------------------------------

The midpoint formula is >>>

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Plugging in the points, we have >>>

\begin{gathered} M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}) \\ M=(\frac{\sqrt[]{20}+\sqrt[]{125}}{2},\frac{\sqrt[]{50}+\sqrt[]{8}}{2}) \\ M=(\frac{2\sqrt5+5\sqrt[]{5}}{2},\frac{5\sqrt[]{2}+2\sqrt[]{2}}{2}) \\ M=(\frac{7\sqrt[]{5}}{2},\frac{7\sqrt[]{2}}{2}) \end{gathered}

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The difference in weights is 1.31 pounds
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