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White raven [17]
3 years ago
13

Marketers with successful brands sometimes hesitate to expand their brands because

Business
1 answer:
Yakvenalex [24]3 years ago
4 0

Available Option:

a. it is costly to maintain many product lines, and it might weaken the brand's meaning.

b. it is often difficult to get additional marketing communications coverage for the brand.

c. the current economy can only support a limited number of product options.

d. manufacturing divisions usually control brand expansion and are often in conflict with the marketing division.

e. Federal Trade Commission regulations limit the number of products that can be marketed under an individual brand name.

Answer:

Option A. It is costly to maintain many product lines, and it might weaken the brand's meaning.

Explanation:

The reason is that adding brand in the existing highly valued brand names require maintaining the brand's meaning and reputation which results in incurring higher costs in quality management, customer locating, making sales and other costs. The poor feedback of a new product can result in the decline in the trust of previous highly reputed brands which can affect the firm severely so the marketers might avoid such inclusions of brands.

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If 5.71 mL of the S2O32- solution are required to reach the endpoint of the titration, what is the molarity of S2O32- in the sol
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Answer: The question is incomplete as some details are missing. here is the complete question ; To standardize a thiosulfate (S2O32-) solution, 10.00 mL of a  1.25×10−2 M   IO3- solutionare treated with excess I- to generate I3- according to Equation 3 on page 162 in the lab manual. If  5.71 mL of the S2O32- solution are required to reach the endpoint of the titration, what is the molarity of thiosulfate in the solution?

Using this equation: I3(aq)+2S2O32-(aq)->3I(aq) + S4O62-(aq)

Explanation:

from the equation ; ClO(aq) + 3I(aq) + H2O(I) ------> I3(aq) + CI(aq) + 2OH(aq) (Equation 1)

from the equation ;  I3(aq)+2S2O32-(aq)->3I(aq) + S4O62-(aq) (equation 2)

from another equation ; IO3- (aq) + 8I-(aq) + 6H+(aq) ----> 3I3-(aq) + 3H2O(I) (Equation 3)

The balancing of equation (1) and equation (2) gives equation 3

Given molarity of IO3- (aq) = 1.25M x 10^-2

from the reaction concentration in equation 3; 1mole of IO3- (aq) gives 3moles of I3-(aq)

therefore moles of I3-(aq) = 3 x 1.25 x 10^-2 = 3.75 x 10^-2M

from the reaction in equation 2 ; I3(aq)+2S2O32-(aq)->3I(aq) + S4O62-(aq)

for I3-(aq), C1 = 3.75 x 10^-2M, V1 = 10.0mL, n1 = 1

for S2O32-(aq), C2 = ?, V2 = 5.71mL, n2 = 2

recalling that C1V1/N1 = C2V2/N2

C2 = C1V1 x n2/V2 x n1

Substituting; C2 = 3.75 x 10^-2M x 10.0mL x 2 / 5.71mL x 1

C2 = 0.131M = is the molarity of S2O32-(aq) in the solution

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Answer:

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