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hammer [34]
3 years ago
7

Can any rational number be an integer?

Mathematics
2 answers:
ludmilkaskok [199]3 years ago
8 0

No, only a rational number is not a fraction or decimal. But any whole number including one with a negative sign.

For example, -1 and 1 could be a integer.

suter [353]3 years ago
3 0

Yes every integer is a rational number, since each integer can be written in the form n/1. For example 5 = 5/1 and thus 5 is a rational number. However, numbers like 1/2, 45454737/2424242, and -3/7 are also rational, since they are fractions whose numerator and denominator are integers.

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Solve and explain please.
deff fn [24]
Are you still doing it.?
4 0
4 years ago
Thomas bought a desk with a retail sales price of $128 and paid $10.37 for sales tax. What is the sales tax rate where Thomas bo
UNO [17]
10.37/128 = 8.1%. Is the rate of tax
7 0
3 years ago
Darryl deposits $1,500 into a savings account that has a simple interest rate of 2.7%. Lori deposits $1,400 into a savings accou
igor_vitrenko [27]
Darryl:
Answer:
A = $1,905.00

(I = A - P = $405.00)

Equation:
A = P(1 + rt)

Lori:

Answer:
A = $1,932.00

(I = A - P = $532.00)

Equation:
A = P(1 + rt)

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3 0
3 years ago
Read 2 more answers
Soap films and bubbles are colorful because the interference conditions depend on the angle of illumination (which we aren't cov
mylen [45]

Answer:

56.39 nm

Step-by-step explanation:

In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,

2t=(m+\frac{1}{2} ).\frac{\lambda}{n}

where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...

Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.

In order to have its longest constructive reflection at the red end (700 nm)

t_1=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_1=\frac{1}{2} .\frac{700}{(2)*(1.33)}\\ \\ t_1=131.58\ nm

Here we take m=0.

Similarly for the constructive reflection at the blue end (400 nm)

t_2=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_2=\frac{1}{2} .\frac{400}{(2)*(1.33)}\\ \\ t_2=75.19\ nm

Hence the thickness difference should be

t_1-t_2=131.58-75.19=56.39 \ nm

7 0
3 years ago
Find the dimensions of the cube,<br> Volume = 64 in
Ksivusya [100]

Answer:

4 in

Step-by-step explanation:

volume = 64 in³

side = cubic root of 64 in³

side = 4 in

Check: If a cube has side 4 in, then its volume is 4 in × 4 in × 4 in = 64 in³.

This shows that the answer 4 in is correct.

4 0
2 years ago
Read 2 more answers
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