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Ivanshal [37]
3 years ago
14

Question no. 6, can anyone help?

Mathematics
1 answer:
monitta3 years ago
6 0
In order to find this you have to set i by itself first we will subtravt 40 from both sides(because 40 is s positive and in order to get rid of a positive you have to use a negative) now we have -40=5i, now divide 5 from both sides to get i=-8, that is what Terry will be givng from tip

Hope this helps
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A discuss moves from P1 (4,8) to P2 (15,17). What is the lincar displacement in the horizontal and vertical directions? What is
Yakvenalex [24]

Answer:

The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.

Step-by-step explanation:

We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

\Delta s = s_2-s_1

And apply it to get the horizontal and vertical displacements.

Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.

Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

\Delta x = x_2-x_1

So we can use the given points P1:(x_1,y_2)  \text{  and  } P_2: (x_2,y_2) on the displacement formula

\Delta x = 15-4\\\Delta x = 11

In the same manner we can look at the y components of those points to find the vertical displacement

\Delta y = 17-8\\\Delta y =9

Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

\tan(\theta) = \cfrac{\Delta y}{\Delta x}

Solving for the angle we get

\theta = \tan^{-1}\left(\cfrac{\Delta y}{\Delta x}\right)

Replacing values

\theta = \tan^{-1}\left(\cfrac{9}{11}\right)

Which give us

\theta = 39.3^\circ

So the projection angle is 39.3 degrees.

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3 years ago
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zloy xaker [14]

Answer:

A_T=150cm^2

Explanation: We need to find the area of the triangle, We know that the area of any right triangle is:

A_T=\frac{1}{2}(b\times h)

Therefore in the information given we have the following:

\begin{gathered} h=20\operatorname{cm} \\ b=15\operatorname{cm} \end{gathered}

Therefore the Area of this triangle is as follows:

\begin{gathered} A_T=\frac{1}{2}(b\times h) \\ \therefore\rightarrow \\ A_T=\frac{1}{2}(20cm\times15cm)=\frac{1}{2}(20\times15)cm^2 \\ A_T=\frac{1}{2}(300)cm^2=150cm^2 \\ \therefore\rightarrow \\ A_T=150cm^2 \end{gathered}

Note! Units are centimeter-squared

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ASHA 777 [7]

Answer:

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Step-by-step explanation:

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Answer:

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