Answer:
Step-by-step explanation:a = m + (p-1)*d
b = m + (q-1)*d
c = m + (r-1)*d
p(b-c) = p*(q-r)*d
q(c-a) = q*(r-p)*d
r(a-b) = r*(p-q)*d
p(b-c)+q(c-a)+r(a-b)
= p*(q-r)*d + q*(r-p)*d +r*(p-q)*d
= (pq-pr+qr-pq+rp-qr)*d
= 0*d = 0
So i prove p(b-c)+q(c-a)+r(a-b)=0 hope this is helpfull
Answer:
???????????????????????????????
Answer:
The value of b is, 8
Step-by-step explanation:
To determine the value of b:
Given:
....[1]
Since, 0x6A represents the hexadecimal form.
To convert this hexadecimal form into decimal form:

⇒
(decimal form)
Now we have to convert this decimal form into octal
8 | 106
8 | 13 | 2
| 1 | 5
1
Then, the octal form we get, 
Substitute this in [1] we have;

On comparing both sides we have;
b = 8
Therefore, the value of b is, 8
Answer:
???????????????????????????????????????
Answer:
y+o+u+t+u+b+e +biggie smalls
Step-by-step explanation: