Answer:
E) Either anaphase I or II
Explanation:
Failure of segregation of homologous chromosomes during anaphase I or failure of segregation of sister chromatids during anaphase II leads to the presence of the abnormal number of chromosomes in resultant gametes. In the given example, the egg mother cell with 48 chromosomes (24 pairs) would enter meiosis I but the failure of one pair of homologous chromosomes to segregate from each other followed by normal meiosis II would result in the formation of two gametes with one extra chromosome and two gametes with one less chromosome.
On the other hand, if the nondisjunction occurs at anaphase II of meiosis II, two normal gametes, one gamete with one extra chromosome and one gamete with one less chromosome will be formed. Therefore, nondisjunction at anaphase I or anaphase II would have resulted in the production of eggs with one extra chromosome.
SI is a base 10 standardized system. I hope this helped and if not I highly recremend talking to your teacher or a parent.
Answer: The statement is false
Explanation:
NONSENSE mutation, NOT MISSENSE mutation causes premature chain (protein) termination.
Missense mutation is simply a kind of point mutation where a single nucleotide is changed to cause substitution of a different amino acid, thus resulting in a non-functional protein.
So, non-functional protein is caused by missense mutation making the statement false
Answer:
They both do cell division and happens in stages, but one produces body cells (skin cells, stumic cells, ext.) and the other produses sperm and egg cells .
