If you would like to solve a = <span>πr^2s + 360 for s, you can do this using the following steps:
</span>a = πr^2s + 360
a - 360 = πr^2s
s = (a - 360) / (πr^2)
The correct result would be s = (a - 360) / (πr^2).
Answer:
3/2 or 1.5
Step-by-step explanation:
0.75 times 4 is 3
0.5 times 4 is 2
Your answer is 3/2 or 1.5
When ever you have percentages, it should be helpful to bear in mind you can express them as multipliers. In this case, it will be helpful.
So, if we let:
a = test score
b = target score
then, using the information given:
a = 1.1b + 1
a = 1.15b - 3
and we get simultaneous equations.
'1.1' and '1.15' are the multipliers that I got using the percentages. Multiplying a value by 1.1 is the equivalent of increasing the value by 10%. If you multiplied it by 0.1 (which is the same as dividing by 10), you would get just 10% of the value.
Back to the simultaneous equations, we can just solve them now:
There are a number of ways to do this but I will use my preferred method:
Rearrange to express in terms of b:
a = 1.1b + 1
then b = (a - 1)/1.1
a = 1.15b - 3
then b = (a + 3)/1.15
Since they are both equal to b, they are of the same value so we can set them equal to each other and solve for a:
(a - 1)/1.1 = (a + 3)/1.15
1.15 * (a - 1) = 1.1 * (a + 3)
1.15a - 1.15 = 1.1a + 3.3
0.05a = 4.45
a = 89
Yes bc 6 groups and a bout 4 are in it ...........
Answer and explanation:
1. In one minute, there would be zero pounds of salt in the bucket because there's 0.25 pounds of salt in one minute and 0.5 gallons of water leaves the bucket in same minute, eliminating the 0.25 pounds of salt.
2. In ten minutes there would be zero pounds of salt because theres 0.25×10= 2.5 pounds of salt and 0.5×10=5 gallons of water would leave the bucket, eliminating the salt.
3. In 60 minutes there would still be zero salt because water leaves the bucket more than salt enters
4. Zero salt too after bucket leaks
5. Zero salt
