Answer:
Answer:
Option B is correct.
Step-by-step explanation:
We will compare the interest earned by both.
Tasha: p = $5000
r = 6% or 0.06
n = 1
So, Amount after a year will be = = $5300
And amount the next year with p = 5300: 5300*1.06= $5618
Additional $5000 at 8%
Here the amount will be = =5400
Next year amount with p = 5400 : 5400*1.08 = $ 5832
Amount in total Tasha will have in 2 years = 5618+5832 = 11450
Thomas:
p = 10000
r = 7% or 0.07
n = 1
After a year the amount will be = =$10700
Amount Next year with p = 10700 : 10700*1.07 = $11449
*****Just after 1 year we can see that Tasha's total amount is high than Thomas. This means at the same consistent rate, each year Tasha's amount will always be higher than Thomas.
So, option B is correct. Tasha’s investment will yield more over many years because the amount invested at 8% causes the overall total to increase faster.
Answer:
37 and 38
Step-by-step explanation:
let the consecutive integers be x-1 and x
If their sum is 75
x-1+x = 75
2x - 1 = 75
2x = 75+1
2x = 76
x = 76/2
x = 38
First integer = x - 1
First integer = 38-1 = 37
Second integer is 38
Hence the integers are 37 and 38
Answer:
1. m∠B=110°
2. 560 cm3
3. Numerical data
4. 2000 cm3
5. 50%
Step-by-step explanation:
1. The explanation of part 1 is given in the attachment.
2. Given dimensions : 10 cm, 8 cm, and 7 cm.
Let Length of cuboid =10 cm
breadth/width of cuboid =8 cm
height of cuboid = 7cm
Volume of cuboid = length *width* height
=( 10 *8*7) cm3
=(560) cm3
3. Age, Birth date and weight are the types/examples of "<u>Numerical Data"</u> because these all are describe in terms of numeric values.
4. 1 liter = 1000 cm3 or 1 cm3 = 0.001 liter
1.5 liters =(1.5*1000) cm3 = (15*100) =1500 cm3
1 dm3 =1000 cm3
0.35 dm3 = (0.35*1000) cm3 = (35*10) cm3 =350 cm3
Given expression: 1.5 litre + 0.35 dm3 + 150 cm3 = <u> </u> cm3
1500 cm3 + 350 cm3 +150 cm3 = <u>2000</u> cm3
5. If A=(1/2)B, then B : A = <u>50</u> %
Ratio: B : A
B : (1/2) B
1: (1/2)
50 % (The value of A is half of the value of B)
You need to multiply 43x43