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belka [17]
3 years ago
13

Rasheed bought two kinds of candy bars, chocolate and toffee, that came in packages of 2 bars each. He handed out 2/3 of the cho

colate bars and 3/5 of the toffee bars. How many packages of chocolates bar did Rasheed buy?
(1) Rasheed bought 1 fewer package of chocolate bars than toffee bars.
(2) Rasheed handed out the same number of each kind of candy bar.
Mathematics
1 answer:
mylen [45]3 years ago
5 0

Answer:

Rasheed bought 9 packages of chocolates bar.

Step-by-step explanation:

Let C be the number of packages of chocolate bars.

Let T be the number of packages of toffee bars.

Rasheed handed out 2/3 of 2C of the chocolate bars and 3/5 of 2T of the toffee bars.

(1) Rasheed bought 1 fewer package of chocolate bars than toffee bars.

Equation becomes:

C=T-1    .....(1)

(2) Rasheed handed out the same number of each kind of candy bar .

Equation becomes:

\frac{2}{3}\times 2C =\frac{3}{5}\times 2T

=> \frac{4C}{3} =\frac{6T}{5}

=> 20C=18T

=> 20C-18T=0

Taking out 2 common, we get

10C-9T=0    ......(2)

Substituting C=T-1 in (2)

10(T-1)-9T=0

=> 10T-10-9T=0

=> T-10=0

T = 10

As C=T-1

C=10-1

C = 9

Therefore, Rasheed bought 9 packages of chocolates bar.

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