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puteri [66]
3 years ago
14

Solving Exponential Equations (lacking a common base) Solve the exponential equation 6u = 22

Mathematics
2 answers:
velikii [3]3 years ago
7 0

Answer:

u = log 22 / log 6

u = 1.725

Step-by-step explanation:

Let's start by saying:

When ever you have an exponential equation with a different base, you attack

evablogger [386]3 years ago
3 0

Answer:

lg22/lg6

Step-by-step explanation:

6^u = 22

lg(6^u) = lg22

ulg6 = lg22

u = lg22/lg6

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Please Answers with steps...will be much appreciated!!!
11Alexandr11 [23.1K]
To solve the exercirses which are shown in the figure attached, you must follow the proccedure below:

 7) (x)=x³-6x²+8x
 (x)=x(x³-6x²+8)
 (x)=(x-4)(x-2)x

 The lenght is: x
 The height is= (x-4)

 8) √(2x+8)-6=4

1. You need to clear the variable "x". Then:

 √(2x+8)=4+6
 √(2x+8)=10
 (√2x+8)²=10²
 2x+8=100
 2x=100-8
 x=92/2
 x=46

 9) l4x+3l=9+2x

 1. To solve the left member, you must evaluate two cases: it could be positive,or negative. Then:

 2. Negative:

 l4x+3l=9+2x
 -4x-3=9+2x
 -4x-2x=9+3
 -6x=12
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 x=-2

 3. Positive:

 l4x+3l=9+2x
 4x+3=9+2x
 4x-2x=9-3
 2x=6
 x=6/2
 x=3
4 0
3 years ago
Kyle is 37 years old and wants to accumulate $1,000,000 by the time he is
Delvig [45]
Ngl idk but just be a nice person and mark as brainliest please
6 0
3 years ago
For brett's birthday his mother gave out colorful birthday hats that were cone shaped. the opening of the bottom of the hat was
nika2105 [10]
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4 0
3 years ago
If (x - h) = 4 and (y - k) = 3, what is the radius of the circle above?
I am Lyosha [343]
(x-h)²+(y-k)²=r² is the equation of a circle with radius of r


so if x-h=4 and y-k=3 then

4²+3²=r²
16+9=r²
25=r²
sqrt both sides
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5 0
3 years ago
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The difference is 160
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