just use what you know about this stuff
(a+36d)/(a+20d) = (a+55d)/(a+36d)
(a+36d)^2 = (a+55d)(a+20d)
a^2+72ad+1296d^2 = a^2+75ad+1100d^2
3ad = 196d^2
3a = 196d
That is, for any value of n,
a=196n
d=3n
So, there is no unique solution.
If n=1, then a=196 and d=3. The terms are
196+20*3 = 256
196+36*3 = 304
196+55*3 = 361
304/256 = 361/304
You can easily verify that it works for any value of n.
Ummm yes please! Thanks so much!!! Merry Christmas
╰(*´︶`*)╯♡
Answer:
You have to upload a pic of you're work?
Step-by-step explanation:
Answer:
No, I don't think so.
Step-by-step explanation:
Answer:
1. F:32 C:0
2. F:212 C:100
3. F:70 C:30
4. F: 97 C: 36.5
Step-by-step explanation:
