Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:
(1)
By Quadratic Formula:
, 
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
11 is the biggest and the 22
Answer:
a. $2,303.59
b. $5,803.59
Step-by-step explanation:
A = P(1 + r)^t
A = 3500(1.017)^30
A = 5803.59
Answer: c 6
Step-by-step explanation:
3 2/3 +2.3...
2.3....=2 1/3
3 2/3 + 2 1/3= 5 3/2
=6
Answer:
x+y-10 -1
Step-by-step explanation:
if x is 3 and y is 6 then 3+6= 9
9-10=-1
