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skelet666 [1.2K]
3 years ago
11

What is the answer to 2-(y+2)=3y

Mathematics
2 answers:
stiv31 [10]3 years ago
7 0

Answer:

Y+=1.25

Step-by-step explanation:

2-(y+2)=3y

-2y+4=3y

4=5y

y=1.25

nexus9112 [7]3 years ago
5 0

Answer:

thx

Step-by-step explanation:

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A food safety guideline is that the mercury in fish should be below 1 part per million​ (ppm). Listed below are the amounts of m
posledela

Answer:

Check the attached document for the solutions, cheers

Step-by-step explanation:

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3 years ago
If a 10 cm radius wheel rotates through 2 radians how many meters has it rolled?
IrinaK [193]
2 radians = 2 full rotations
pi = 3.14

circumference of wheel = 2(pi)r
= 20 * 3.14
=62.8 cm
= 0.628m

meters rolled = 0.628 * 2
=1.256 m
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2 years ago
Help will mark as brainliest
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2 years ago
A gym membership charges $100 for a start up fee and $40 a month for
slamgirl [31]

The equation that represents the cost of membership is  $100 + $40c

The cost of 1 year membership is $580.

The number of months you have paid for is 9 months.

<h3>What is the equation that represents the cost of the gym membership?</h3>

The cost of gym membership is the sum of the fixed cost and the variable cost. The fixed cost is the start-up fee while the variable cost is the cost per month.

The equation that represents the cost of the gym membership is: c = $100 + $40m

Where m represents the number of months

The cost of 1 year membership =  $100 + $40(12)

$100 + $480 = $580

How many months would $460 cover = ($460 - $100) / 40 = 9 months

To learn more about fixed cost, please check: brainly.com/question/25879561

6 0
2 years ago
What is a necessary step for constructing perpendicular lines through a point off the line?
Nostrana [21]

Answer:

Find another point on the perpendicular line.

Step-by-step explanation:

Given an original line "m", and a point off the line "Q", in order to construct a second line "p", meant to be perpendicular to "m" through the point "Q", fundamentally, the only truly necessary step to construct a perpendicular line through is to find another point on the yet-to-be-found perpendicular line.

Most often, this is accomplished by exploiting the fact that "p" is the set of all points that are equidistant from any pair of points that are symmetric about "p".

Since the symmetry must be about "p", and we don't even know where "p" is, one often finds two points on "m" that are equidistant from "Q".

This can be accomplished by adjusting a compass to a fixed radius (larger than the distance from "Q" to "m"), and making an arc that intersects "m" in two places.  Those two places will be equidistant from "Q", and are simultaneously on line "m".  Thus, these two points, "A" & "B" are symmetric about "p".

Since "A" & "B" are symmetric about "p", they are equidistant from "p", and are on "m".  One could try to find the point of intersection between "p" and "m" through construction, but this is unnecessary.  We need only find a second point (besides "Q") that is equidistant from "A" & "B", which will necessarily be a point on "p", to form the line perpendicular to "m".

To do this, fix the compass with any radius, and from "A" make a large arc generally in the direction of "B", and make the same radius arc from "B" in the direction of "A" such that the two arcs intersect at some point that isn't "Q".  This point of intersection we can call point "T", and the line QT is line "p", the line perpendicular to the original line, necessarily containing "Q".

8 0
2 years ago
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