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3 years ago

6

PLEASE HELP SO I MADE A STAIN ON MY PARENTS COUCH SO I USED STAIN REMOVER BUT THE STAIN REMOVER LEFT A STAIN AND IM NOT SURE HOW

TO TAKE CARE OF IT. PLEASE HELP

1 answer:

lana66690 [7]3 years ago

8 0

Answer:

that's hardly visible i wouldn't worry about it

Step-by-step explanation:

1+1=2

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-5,-2 5,-4 what's the slope

bekas [8.4K]

Answer:

Slope = -1/5

Step-by-step explanation:

(-5, -2)(5, -4)

Slope: $\frac{y^{2}-y^{1} }{x^{2}- x^{1} } = \frac{-4-(-2)}{5-(-5)} =\frac{-4+2}{5+5} =\frac{-2}{10}=-\frac{1}{5}$

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2 years ago

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Find the limit, if it exists, or type dne if it does not exist.

Phantasy [73]

$\displaystyle\lim_{(x,y)\to(0,0)}\frac{\left(x+23y)^2}{x^2+529y^2}$

Suppose we choose a path along the $x$ -axis, so that $y=0$ :

$\displaystyle\lim_{x\to0}\frac{x^2}{x^2}=\lim_{x\to0}1=1$

On the other hand, let's consider an arbitrary line through the origin, $y=kx$ :

$\displaystyle\lim_{x\to0}\frac{(x+23kx)^2}{x^2+529(kx)^2}=\lim_{x\to0}\frac{(23k+1)^2x^2}{(529k^2+1)x^2}=\lim_{x\to0}\frac{(23k+1)^2}{529k^2+1}=\dfrac{(23k+1)^2}{529k^2+1}$

The value of the limit then depends on $k$ , which means the limit is not the same across all possible paths toward the origin, and so the limit does not exist.

8 0

3 years ago

Given a dilation around the origin, what is the scale factor K?<br><br> Do, K = (20,16) → (-5,-4)

Rudik [331]

Answer:

Scale factor, K = -1/4

Step-by-step explanation:

Dilation of any image changes its size and the shape remains same.

The scale factor is the ratio of dilated image to original image.

Dilation rule: (x, y) → (kx, ky), where k is the scale factor.

It means k = x₂/x₁ or y₂/y₁

K = -5/20 = -1/4 or K = -4/16 = -1/4.

<u>The negative value of scale factor (K) indicates dilations with 180 degree rotation of the dilated image.</u>

Hence the scale factor is K = -1/4.

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3 years ago

If x=3 and y=-2 then<br> x2 - xy<br> x²+2y

Naddika [18.5K]

Answer:

Step-by-step explanation:

(3)*2=6

-

(3)*(-2)=-6

6-(-6)=12

3*3=9

+2(-2)=-4

9+ -4= 5

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3 years ago

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Assume that you assign the following subjective probabilities for your final grade in your econometrics course (the standard GPA

rodikova [14]

Answer:

$E(X) = 4*0.2 +3*0.5+ 2*0.2 +1*0.8+ 0*0.02= 2.78$

So then the best answer for this case would be:

C. 2.78

Step-by-step explanation:

For this case we have the following probabability distribution function given:

Score P(X)

A= 4.0 0.2

B= 3.0 0.5

C= 2.0 0.2

D= 1.0 0.08

F= 0.0 0.02

______________

Total 1.00

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

If we use the definition of expected value given by:

$E(X) = \sum_{i=1}^n X_i P(X_I)$

And if we replace the values that we have we got:

$E(X) = 4*0.2 +3*0.5+ 2*0.2 +1*0.8+ 0*0.02= 2.78$

So then the best answer for this case would be:

C. 2.78

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3 years ago