Rectangle, triangle, and I believe square
This one is so easy that your brain refuses to accept it.
It's looking for a harder answer, but can't find it !
You're totally correct, as far you went. x² + 2x does = -1
Now add ' 1 ' to each side: x² + 2x + 1 = 0
Can you factor that quadratic ?
Can you mash it through the quadratic formula ?
Actually, it's the simplest possible perfect square.
x² + 2x + 1 = (x + 1)²
So the solutions of x² + 2x + 1 = 0 are both x = -1 .
Don't say anything.
I know it's embarrassing.
Answer:
The answer is A as when simplified the number is 125^x/3
and the only one taht represents this is a
The missing coordinates of the parallelogram is (m + h, n).
Solution:
Diagonals of the parallelogram bisect each other.
Solve using mid-point formula:
Here
<u>To find the missing coordinate:</u>
Let the missing coordinates by x and y.
Here
Now equate the x-coordinate.
Multiply by 2 on both sides of the equation, we get
m + h = x
x = m + h
Now equate the y-coordinate.
Multiply by 2 on both sides of the equation, we get
n = y
y = n
Hence the missing coordinates of the parallelogram is (m + h, n).
11 and 12
7 and 512
12 and 10
0 and 78
left side numerator
right side denominator