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sertanlavr [38]
3 years ago
13

If the length of AO is double the length of CO, the length of BO is?

Mathematics
1 answer:
andreev551 [17]3 years ago
7 0

BO is double that of DO. In other words, BO is two times longer than DO. The answer is choice B

For example, if DO were 3 units long, then BO would be 6 units long (2*3 = 6). This works because the triangles DCO and BAO are similar triangles. The corresponding sides are in the same ratio or proportion to one another. The larger triangle (BAO) has sides that are twice as long as the smaller triangle's (DCO) corresponding sides.

Side note: we can prove the triangles to be similar using the AA (angle angle) similarity theorem. The first pair of angles are the vertical angles DOC and BOA which are congruent to each other.The second pair is CDB and ABD which are congruent by the alternate interior angle theorem. Check out the attached image for a visual.

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Simplify the radical expression completely LaTeX: 3\sqrt{5}\:-\:3\sqrt{11}+2\sqrt{121}-3\sqrt{90}3 5 − 3 11 + 2 121 − 3 90 A. La
lora16 [44]

Answer:

3\sqrt{5}\:-\:3\sqrt{11}+22-9\sqrt{10}

Step-by-step explanation:

Given

3\sqrt{5}\:-\:3\sqrt{11}+2\sqrt{121}-3\sqrt{90}

Required

Simplify the expression

3\sqrt{5}\:-\:3\sqrt{11}+2\sqrt{121}-3\sqrt{90}

Express the square root of 121 as 11

3\sqrt{5}\:-\:3\sqrt{11}+2 * 11-3\sqrt{90}

3\sqrt{5}\:-\:3\sqrt{11}+22-3\sqrt{90}

Express 90 as 9 * 10

3\sqrt{5}\:-\:3\sqrt{11}+22-3\sqrt{9 * 10}

Split the surd to 2

3\sqrt{5}\:-\:3\sqrt{11}+22-3\sqrt{9} * \sqrt10}

Express the square root of 9 as 3

3\sqrt{5}\:-\:3\sqrt{11}+22-3 * 3 * \sqrt10}

3\sqrt{5}\:-\:3\sqrt{11}+22-9 * \sqrt10}

3\sqrt{5}\:-\:3\sqrt{11}+22-9\sqrt{10}

Hence, the result of the expression is

3\sqrt{5}\:-\:3\sqrt{11}+22-9\sqrt{10}

7 0
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