Question

Please help ASAP!! Algebra 2 Solve for x. 1/8x−5<−8 or 7x−4≥38

Answer 1

1/8x - 5 < - 8 7x - 4 > 38
+ 5 +5 +4 +4
1/8x < -3 7x > 42
÷1/8 ÷1/8 ÷7. ÷7
x = 24 x > 6

Answer 2

Answer:

$x\in (-\infty,-24)\cup [6,\infty)$

Step-by-step explanation:

The given compound inequality is

$\frac{1}{8}x-5$ or $7x-4\geq 38$

Solve each inequality.

On solving first inequality we get

$\frac{1}{8}x-5$

Add 5 on both sides.

$\frac{1}{8}x-5+5$

$\frac{1}{8}x$

Multiply both sides by 8.

$x$              .... (1)

On solving second inequality we get

$7x-4\geq 38$

Add 4 on both sides.

$7x\geq 42$

Divide both sides by 7.

$x\geq 6$                .... (2)

Using (1) and (2) the value of x is either less than -24 or greater than or equal to 6.

$x\in(-\infty,-24)\cup [6,\infty)$