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3 years ago

HELP PLEASE !!!!!!!!!!!!!!

1 answer:

6 0

This is the answer for your question above

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GalinKa [24]

9514 1404 393

Answer:

x - 4

Step-by-step explanation:

The expression simplifies to ...

$\sqrt{x^2-8x+16}=\sqrt{(x-4)^2}=|x-4|$

For x ≥ 4, the argument of the absolute value function is non-negative, so it remains unchanged. The simplified expression is ...

x - 4 . . . . for x ≥ 4

6 0

2 years ago

butalik [34]

This is what I have found, hope this helps!!!

6 0

3 years ago

MrRissso [65]

Solving for x you would get X=6

7 0

3 years ago

valkas [14]

Answer:

x-ints: (2,0) & (4,0)

y-int: (0,-8)

vertex: (3,1) *highest point of the graph

line of symmetry: x = 3 *x-value in the middle of x-ints

a value is -# *if parabola points done it's negative, if it points up it's positive

5 0

3 years ago

Keith_Richards [23]

Answer:

A= T/CB - 6/B

that is the answer to the question

3 0

3 years ago