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here the equation of path is -2x-7=y
let us find slope of this line by using y=mx+b
so slope m=-2
now new path is perpendicular to this path.
product of slopes of perpendiculars is -1
so slope of new path is 1/2
now it passes through (-2,-3) with slope 1/2
using y=mx+b to get value of b
-3=1/2(-2) +b
b=-2
plugging m=-1/2 and b=-2 in y=mx + b to get the final equation as
y=(-1/2) x -2 is the equation of new path
Answer:
1. You first have to find the slope
2. Next, you have to find the y-intercept
3. Finally, you have to put it in y = mx + b form.
Step-by-step explanation:
The slope of 2 points is; 
The y-intercept is; 
y = mx + b
m is always the slope
b is always the starting point or y-intercept
A^2+b^2= c^2
3^2+4^2=c^2
9+16=c^2
25=c^2
5=c
They mowed total of 11/15 (5/15 + 2/5) already, so they still have 4/15.
