<em>Standard equation of hyperbola is </em>
.
<em>Comparing given info with standard equation, we get
</em>a(vertices)= +3 and -3
foci =
.
<em>Comparing given info with standard equation, we get
</em>a(vertices)= +3 and -3
foci =
Choose the correct simplification of (7x^3y^3)^2.
1 answer:
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Graph the easier one first
from 5-x for 3≤x≤5
so we see the ≤ for both so filled in circles
graph f(x)=5-x from x=3 to x=5
plot (3,2) and (5,0) and connect them and fill in the points/dots
that's only the 3rd graph
from 5-x for 3≤x≤5
so we see the ≤ for both so filled in circles
graph f(x)=5-x from x=3 to x=5
plot (3,2) and (5,0) and connect them and fill in the points/dots
that's only the 3rd graph