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2 years ago

Choose the correct simplification of (7x^3y^3)^2.

Mathematics

1 answer:

Tamiku [17]2 years ago

7 0

Answer: third option, 49x⁶y⁶

Justification:

1) Given: $(7x^3y^3)^2$

2) Property: power of a product

$(7)^2(x^3)^2(y^3)^2$

3) Property: power of power

$49x^6y^6$

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The Happy-Go-Lucky Beach was 163 feet long from parking lot to high tide. After last year's hurricane came ashore, the beach onl

ANTONII [103]

Answer:

About 5.5% decrease

Step-by-step explanation:

Here, we want to calculate the percentage increase or decrease and its value.

The first thing to do here is to check if we are going to have a decrease or an increase.

since the value before the change is higher than the value after the change, then what we have is a decrease.

Mathematically, the percentage decrease is calculated as follows;

% decrease = (old value - new value)/old value * 100%

old value = 163 feet

new value = 154 feet

% decrease = (154-163)/163 * 100%

% decrease = -9/163 * 100%

% decrease = -5.52%

Thus the best answer is about 5.5% decrease

4 0

3 years ago

3x-2y=10 solving equations

Schach [20]

Answer:

Step-by-step explanation:

3x-2y= 100

3x= 10 +2y

x =(10+2y)/

8 0

1 year ago

Can someone plz help me. How can you find the inequalities of 11/15 and 5/7. Next 5/9 and 7/13. Next 11/15 and 5/7. Lastly 5/9 a

LekaFEV [45]

To make this a little clearer, let's give the pairs of inequalities the same denominator:

Question 1:
 $\frac{11}{15}$ ? $\frac{5}{7}$
First, apply the common denominator to the first fraction:
$(\frac{11}{15})7 \\ \frac{11}{15} * \frac{7}{7} \\ \frac{11*7}{15*7} \\ \frac{77}{105}$
Do the same for the second: $15( \frac{5}{7}) \\ \frac{5}{7}* \frac{15}{15} \\ \frac{5*15}{7*15} \\ \frac{75}{105}$
Nest, compare the two fractions:
$\frac{77}{105} \ \textgreater \ \frac{75}{105}$
Therefore:
$\frac{11}{15}$ > $\frac{5}{7}$

Question Two:
$\frac{5}{9}$ ? $\frac{7}{13}$
Apply the common denominator to fraction one:
$13( \frac{5}{9}) \\ \frac{5}{9} * \frac{13}{13} \\ \frac{5*13}{9*13} \\ \frac{65}{117}$
Fraction two:
$9(\frac{7}{13}) \\ \frac{7}{13} * \frac{9}{9} \\ \frac{7*9}{13*9} \\ \frac{63}{117}$
Evaluate:
$\frac{65}{117}$ > $\frac{63}{117}$
Therefore:
 $\frac{5}{9}$ > $\frac{7}{13}$

Hope this helps!

5 0

3 years ago

Find 4ab when (a+b)=15 and (a-b)=12

Volgvan

A + b = 15 ..... eq 1
a – b = 12 ...... eq 2

So a = 15 – b
Substitute in eq 2 :

15 – b – b = 12
15 – 2b = 12
–2b = 12 – 15
b = 1.5

So a = 15 – 3/2 = 13.5

4ab = 4 x 13.5 x 1.5 = 81

4 0

3 years ago

Read 2 more answers

If x2 − 8xy + 12y2 = 8 and x − 6y = 3, then x − 2y = A) 18 B) 24 C) 36 D) 8 3

IgorLugansk [536]

It is the last answer letter D 8/3

3 0

3 years ago