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Shtirlitz [24]
3 years ago
14

Simplify the following expression

Mathematics
1 answer:
lukranit [14]3 years ago
6 0

Answer:

x-3 / (x+1)(5x-2)

Step-by-step explanation:

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Solve for t. You must write your answer in fully simplified form. <br> −19= 7t
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Answer: dot know srry

Step-by-step explanation:

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How many feet are in 100 meters if 1 meter is 1.09 yards? Will mark brainliest if you include clear steps. Thank you!
kramer
Well, there are 3 feet in 1 yard, and 1.09 yards in 1 meter, so then

\bf 100~\underline{m}\cdot \cfrac{1.09~\underline{yd}}{\underline{m}}\cdot \cfrac{3~ft}{\underline{yd}}\implies \cfrac{100\cdot 1.09\cdot 3~ft}{1}\implies 327~ft

notice, we use the ratio, and whichever unit you want cancelled, you simply flip the ratio to have it cancelled, if the "m" is atop and you need that cancel, use the ratio with the "m" at the bottom, m/m = 1, and so they cancel out, and so on.
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U( w f +u ) = m + j <br> solve for u : u=<br> solve for f :F=
vovikov84 [41]

\textbf{Solve for u:}\\\\u(wf+v)=m+j\\\\\implies u = \dfrac{m+j}{wf+v}\\\\\textbf{Solve for f:}\\\\u(wf+v) = m+j\\\\\implies uwf+uv = m+j\\\\\implies uwf = m+j-uv\\\\\implies f=\dfrac{m+j-uv}{uw}

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2 years ago
Help plz,.<br>cos5A - cosA / sin5A+sinA-2sin3A=cotA<br>prove it.​
RSB [31]

Answer:

here is your answer of the question

8 0
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Read 2 more answers
Give an example of each of the following, or argue that such a request is impossible.
Masteriza [31]

Answer and Step-by-step explanation:

Solution:

(a) Let (bn) be a bounded sequence of (an) then, Bolzano- Weierstrass theorem,

(bn) contains a subsequence that is converges.

(b) The sequence :

Xn = 1 + (-1) n / 2 + 1/n

Clearly, (xn) does not contain 1 or 0.

If we take sequence (x2n), then it converges to 1 and when we take sequence (x2n+1),

Then it converges to 0.

(c) The sequence:

1

1,1/2

1, 1/2, 1/3

1, 1/2, 1/3, 1/4

i.e

(xn) = (1,1/2, 1, 1/2, 1/3, …)

Then, the subsequence (xn) that is identically ½ in second column and 1/3 is third column and so on.

It has sub sequence that converges to every point in infinite set {1, 1/2, 1/3, 1/4, 1/5…}.

(d) The sequence

{1, 1/2, 1/3, 1/4, 1/5…}

if we take sequence of given set, then, this set converges to zero. This is not contained in it.

If (xn) converges to every point in set {1, 1/2, 1/3 …} then there exists subsequence which converges to 0. And 0 does not belong to given set.

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3 years ago
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