F(x)=3x-2

A figure is part blue and part red.it is 5/8 red what part of the figure is blue

oksian1 [2.3K]

If $\frac{5}{8}$ is red, than the remaining $\frac{3}{8}$ would be blue. $\frac{5}{8}$ + $\frac{3}{8}$ would give you $\frac{8}{8}$ .

8 0

2 years ago

320÷÷((11−9)32(11−9)32) x 8 =

jarptica [38.1K]

320÷((11−9)32(11−9)32) x 8

320÷((352-288)(352-288) x 8

320÷(64 x 64) x 8

320÷4096 x 8

0.078125 x 8

0.625

Answer:0.625

3 0

2 years ago

the graph of y=e^tanx-2 crosses the x axis at one point in the interval [0,1]. What is the slope of the graph at this point? I g

Svetlanka [38]

Y = e^tanx - 2

To find at which point it crosses x axis we state that y= 0

e^tanx - 2 = 0
e^tanx = 2
tanx = ln 2
tanx = 0.69314
x = 0.6061

to find slope at that point first we need to find first derivative of funtion y.

y' = (e^tanx)*1/cos^2(x)

now we express x = 0.6061 in y' and we get:
y' = k = 2,9599

3 0

2 years ago

The American Water Works Association reports that the per capita water use in a single-family home is 63 gallons per day. Legacy

Debora [2.8K]

Answer:

$t=\frac{60-63}{\frac{8.9}{\sqrt{28}}}=-1.784$

$df=n-1=28-1=27$

$p_v =P(t_{(27)}$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is less than 63 gallons per day at 1% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=60$ represent the sample mean

$s=8.9$ represent the sample standard deviation

$n=28$ sample size

$\mu_o =68$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is less than 63, the system of hypothesis would be:

Null hypothesis: $\mu \geq 63$

Alternative hypothesis: $\mu < 63$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{60-63}{\frac{8.9}{\sqrt{28}}}=-1.784$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=28-1=27$

Since is a one side lower test the p value would be:

$p_v =P(t_{(27)}$

Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is less than 63 gallons per day at 1% of signficance.

5 0

3 years ago

For simple linear regression, y = β0 + β1x + u, which one of the following statements is true?

RSB [31]

Answer:

Option a) u is called the "error term". It is the error we make in prediction

Option d) x is called the independent variable because x is independent from y and u.

Step-by-step explanation:

We are given the following information in the question:

$y = \beta_0 + \beta_1x + u$

where y is the dependent variable, x is the independent variable.

$\beta_0$ : It is the value of y when x is zero, that is y-intercept.

$\beta_1$ : It is the coefficient of x in predicting the dependent variable y.

u is the error term.

An error term represents the margin of error.
It refers to the sum of the deviations within the regression line, that is the difference between the predicted value and the observed value of y.

Thus, Option A) u is the error term and Option D) x is called the independent variable because x is independent from y and u are the correct answer.

6 0

2 years ago