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3 years ago

7

Does the transformation represent a dilation? Why or

1 answer:

k0ka [10]3 years ago

7 0

Answer: A: no, because each vertex is not multiplied by the same scale factor.

Step-by-step explanation: got it right on Edge 2020!

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Hurry and respond with how you got it!

Sergeeva-Olga [200]

a = 6.2

Solution:

Given ABC is triangle.

AC = b = 8, BA = c = 11, ∠A = 32.2°

BC = a

To find the length of a:

Law of cosines:

$a^{2}=b^{2}+c^{2}-2 b c \cdot \cos A$

$a^{2}=8^2+11^{2}-2 \times 8 \times 11 \cdot \cos 32.2^\circ$

$a^{2}=64+121-174 \cdot \cos 32.2^\circ$

$a^{2}=185-174 (0.8461)$

$a^{2}=185-147.221$

$a^{2}=37.779$

Taking square root on both sides of the equation.

a = 6.1464

a = 6.2

The length of BC is 6.2.

5 0

3 years ago

Please I need help :(

bixtya [17]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Pls help i will give brainliest

Dominik [7]

Well first of all the shorter pipe would be 160ft bc 120/3 is 40 and 40*4 is 160 so the shorter piece is 160ft and 160+12 is 172 so the longer piece of pipe would be 172ft

I’m pretty sure I’m correct, lemme know if I’m not
Hope this helps :)

6 0

3 years ago

Which expression is equivalent to 16x + 42y?<br>1- 7(2x+6y)<br><br>2- 6(3x+7y)<br><br>3- 2(8x+11y)

White raven [17]

I don’t believe any are correct that you have

7 0

3 years ago

What is the following quotient? 2/ square root 13 + square root 11

enot [183]

Given : $\frac{2}{\sqrt{13}+\sqrt{11}}$

$\mathrm{Multiply\:by\:the\:conjugate}\:\frac{\sqrt{13}-\sqrt{11}}{\sqrt{13}-\sqrt{11}}$

$=\frac{2\left(\sqrt{13}-\sqrt{11}\right)}{\left(\sqrt{13}+\sqrt{11}\right)\left(\sqrt{13}-\sqrt{11}\right)}$

\left(\sqrt{13}+\sqrt{11}\right)\left(\sqrt{13}-\sqrt{11}\right)

$\mathrm{Apply\:Difference\:of\:Two\:Squares\:Formula:\:}\left(a+b\right)\left(a-b\right)=a^2-b^2$

$a=\sqrt{13},\:b=\sqrt{11}$

$=\left(\sqrt{13}\right)^2-\left(\sqrt{11}\right)^2$

$\left(\sqrt{13}\right)^2-\left(\sqrt{11}\right)^2=13-11=2$

$=\frac{2\left(\sqrt{13}-\sqrt{11}\right)}{2}$

$\mathrm{Divide\:the\:numbers:}\:\frac{2}{2}=1$

$=\sqrt{13}-\sqrt{11}$

Therefore, correct option is $D.\\\sqrt{13} - \sqrt{11}$

4 0

3 years ago

Read 2 more answers