I have taken that test (although I don't see you're statements)
I believe the statements to choose from are:
A.) The slope of the line is −10.
B.) The slope of the line is 3.
C.) One point on the line is (3, 6).
D.) One point on the line is (3,−6)
<u>The answers are:</u>
A.) The slope of the line is -10
D.) One point on the line is (3,-6)
<u>Explanation: </u>
The given equation of line is (1). The point slope form of a line is (2) Where m is the slope of line and (x₁,y₁) are points. On comparing (1) and (2) we get The slope of given line is -10 and the line passing through the points (3,-6).
<u>ANSWER</u>
A. (4,12)
<u>EXPLANATION</u>
The equations are:
and
To eliminate a variable we make the coefficients of that variable the same in both equations.
It is easier to eliminate x.
We multiply the first equation by 2 to get:
We add equations (2) and (3).
Divide both sides by 23
Put x=4 into equation (1).
The solution is (4,12)
Answer:
C is correct.
Step-by-step explanation:
Khan Academy said so.
Looks complicated, sorry wish I could help
If you have at least as many equations as your have unknown variables, the 'system' is solvable (unless the equations are copies of eachother).
In this case, isolate one letter and plug it in the other. I'm going for the 2a in the bottom one (it doesn't matter)
2a - 4b = 12 => (divide by two and move the b's to the other side)
a = 6 + 2b. (plug this one into the top equation)
4(6+2b) + 6b = 10 => 24+8b+6b = 10 => 24 + 14b = 10 => 14b = -14 => b=-1
a = 6 + -2 = 4.
So a=4 and b=-1.
