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mr Goodwill [35]
3 years ago
7

Solve the system of equations. \begin{aligned} & -10x+3y = 5 \\\\ & x=y-4 \end{aligned} ​ −10x+3y=5 x=y−4 ​

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
7 0

Answer:

x = 1

y = 5

Step-by-step explanation:

You can use either substitution or elimination for this problem. I will use substitution.

Step 1: Replace x in the 1st equation

-10(y-4) + 3y = 5

-10y + 40 + 3y = 5

-7y = -35

y = 5

Step 2: Plug <em>y </em>into an original equation to find <em>x</em>

x = 5 - 4

x = 1

And you have your final answers!

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AlladinOne [14]
The solutions or roots to this equation is found by solving for x. We can do this a couple ways either by FOIL or quad formula

3x^2+6x+6=0
3(x^2+2x+2)=0

x^2+2x+2=0 we cant FOIL this out so we use the quad formula

x= [(-b+\-sqrt(b^2-4ac))/2a]

x= -2+\- sqrt(4-4(1)(2))/2(1)
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So we have complex roots since our quad formula returned a negative number. Whenever the quad formula answer is positive we have two roots/solutions, when it is zero we have one root/solution, and whenever it is negative we have Complex roots/solutions

Hope this helps. Any questions please just ask. Thank you.
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3 years ago
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natta225 [31]

Answer:

x=9

Step-by-step explanation:

First, distribute the negative sign, changing (2x+9) to -2x-9

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