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Paraphin [41]
1 year ago
13

The bar diagram represents 24 hours in one day and shows a mark at 30%If you sleep 30% of the day, how many hours do you sleep?

Enter your answer in the box24Hours sleptPercent0%30%100%hoursPlease help
Mathematics
1 answer:
horrorfan [7]1 year ago
8 0

Let:

100%---------------->24h

30%------------------>xh

Using cross multiplication:

\begin{gathered} \frac{100}{30}=\frac{24}{x} \\ solve_{\text{ }}for_{\text{ }}x\colon \\ x=\frac{30\cdot24}{100} \\ x=\frac{720}{100}=7.2h \end{gathered}

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Hey guys i just joined how do i do this
Sergeeva-Olga [200]

Answer: you can ask questions your struggling with and people like me will help you answer them. You can also help other people answer their questions and get points for it

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Suppose in the University of Manitoba, 40% of the students live in apartments. If 600 students are randomly selected, then the a
just olya [345]

Answer:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and X \sim Bin(n=600, p =0.4)

And we want this probability:

P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.
[tex]np=600*0.4=240\geq 10

n(1-p)=600*(1-0.4)=360 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=600*0.4=240

\sigma=\sqrt{np(1-p)}=\sqrt{600*0.4(1-0.4)}=12

And then X \sim N (\mu = 240, \sigma= 12)

And we are interested on the following probability:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

6 0
3 years ago
. A trader bought A TV set for Birr 2000 and sold it at loss of 11/2% what:was the selling price?​
olga nikolaevna [1]

Answer:

1890

Step-by-step explanation:

Loss = 11/2 % = 5.5 %

Cost price = 2000

Loss = 5.5% of cost price

         = 5.5% * 2000

         = \frac{5.5}{100}*2000\\\\= 5.5*20\\= 110

Selling price = Cost price - loss

                      = 2000 - 110

                      = 1890

6 0
3 years ago
Kurt earns $7 per hour for doing chores. his goal is to make at least $35 each week
Yuri [45]

Answer:


Step-by-step explanation:

This is what i get what i understand from your question .

Kurt earns $7 per hour for doing chores. his goal is to make at least $35 each week


So ,

$7 =per hr

X= unknown hrs

$35= goal


7 x =35


Divide both sides by 7 to get x alone representing hrs.


X= 35/7

X= 5


So 5 hrs per week to make 35 a week.


5×7=35

35=35

5 0
3 years ago
Least common multiple of 8 and 56??
scoray [572]

Answer:

56

Step-by-step explanation:

8x7=56

56x1=56

5 0
3 years ago
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