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Papessa [141]
3 years ago
6

Simplify 4(2x^3y^4)^4/2(2x^2y^6)^3. Show your work. Please help ASAP!!

Mathematics
1 answer:
vovikov84 [41]3 years ago
5 0

Answer:

The simplified expression to the given expression is \frac{4x^6}{y^2}

Therefore \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}

Step-by-step explanation:

Given fractional expression is \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}

To simplify the given expression as below :

\frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}

=\frac{2(2x^3y^4)^4}{(2x^2y^6)^3}

=\frac{2[(2)^4(x^3)^4(y^4)^4]}{(2)^3(x^2)^3(y^6)^3}  ( using the property (a^m)^n=a^{mn})

=\frac{2[(2)^4(x^{12})(y^{16})]}{(2)^3(x^6)(y^{18})}

=2[(2)^4(x^{12})(y^{16})](2)^{-3}(x^{-6})(y^{-18})  (  ( using the property a^m=\frac{1}{a^{-m}} )

=2[2^{4-3}x^{12-6}y^{16-18}]( using the property a^m.a^n=a^{m+n} )

=2[2^1x^6y^{-2}]

=\frac{4x^6}{y^2} ( using the property a^m=\frac{1}{a^{-m}} )

Therefore the simplified expression is \frac{4x^6}{y^2}

Therefore \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}

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I really need the help please and thank you
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Answer:

B.  f^{-1}(x)=\frac{x-4}{5}

Step-by-step explanation:

To find the inverse of a function/equation:

  1. Replace f(x) with y: y=5x+4
  2. Switch x and y: x=5y+4
  3. Solve for y: x-4=5y   ->    y=\frac{x-4}{5}
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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