Answer:
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https://mathbitsnotebook.com/Algebra1
13pi/12 lies between pi and 2pi, which means sin(13pi/12) < 0
Recall the double angle identity,
sin^2(x) = (1 - cos(2x))/2
If we let x = 13pi/12, then
sin(13pi/12) = - sqrt[(1 - cos(13pi/6))/2]
where we took the negative square root because we expect a negative value.
Now, because cosine has a period of 2pi, we have
cos(13pi/6) = cos(2pi + pi/6) = cos(pi/6) = sqrt[3]/2
Then
sin(13pi/12) = - sqrt[(1 - sqrt[3]/2)/2]
sin(13pi/12) = - sqrt[2 - sqrt[3]]/2
Answer: Intrest is 1575 the total is 4075
Step-by-step explanation: PLEASE GIVE BRAINLIEST IT HELPS ALOT
Foil the right side. Multiply first, outer, inter, and the last terms. The right side is equal to x^2 + 11x + 18x. N is 11.