Given, the ratio of blocks A, B, C,D are in the ratio 4:7:3:1
Let us consider the common ratio to be ‘x’.
So, toy blocks with alphabet A is 4x and
toy blocks with alphabet B is 7x and
toy blocks with alphabet C is 3x and
toy blocks with alphabet D is x
Again, the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks.
As no. of ‘A’ and ‘C’ blocks are 4x and 3x respectively.
So,
4x=50 + 3x
x=50
Thus, the number of ‘B’ blocks is 7x = 7(50) = 350
350 is the required number.
Hello :
f(x) = (x-5)(x+2i)
= x² +2ix -5x-10i
f(x) = x² +(2i-5)x -10i
<span>coefficients : a =1 b = 2i-5 c =-10i</span>
Step-by-step explanation:
I'll help if you'd like
Answer:
Answer is C.
Step-by-step explanation:
