1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Margaret [11]
3 years ago
6

What is the total number of moles of solute contained in 0.5 liter of 3.0 m

Chemistry
1 answer:
myrzilka [38]3 years ago
4 0

Based on science 4) 1) 0.25M  

2) 0.66M  

3) 1.5M  

4) 4.0M ––> Therefore, this is the most concentrated  

5) 30g NaOH(1 mol NaOH / 40gNaOH) = 0.75 mol NaOH / 0.500L = 1.5M NaOH (3)  

6) 1) 1.0 mol / L(1 L) = 1 mol H2SO4  

2) 1 mol / L (2 L) = 2 mol H2SO4  

3) 0.50 mol / L ( 1.0L) = 0.50 mol H2SO4 ––>

7) 0.200 mol / L (1 L)(74.6g / mol) = 14.92g (2)  

8) 0.25 mol / 0.250 L = 1 mol / L = 1M (1)  

This is the answer  : 1m

You might be interested in
A compound with an approximate molar mass of
Sauron [17]
G about the answer if I don’t do this I Will fail!!!!!! NO LINKS NO LYING
4 0
3 years ago
Complete the dissociation reaction and the corresponding Ka equilibrium expression for each of the following acids in water. (Ty
anastassius [24]

Answer :

(A) The dissociation reaction of HC_2H_3O_2 will be:

HC_2H_3O_2(aq)\rightleftharpoons H^+(aq)+C_2H_3O_2^-(aq)

The equilibrium expression :

K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}

(B) The dissociation reaction of Co(H_2O)_6^{3+} will be:

Co(H_2O)_6^{3+}(aq)\rightleftharpoons H^+(aq)+Co(H_2O)_5(OH)^{2+}(aq)

The equilibrium expression :

K_a=\frac{[H^+][Co(H_2O)_5(OH)^{2+}]}{[Co(H_2O)_6^{3+}]}

(C) The dissociation reaction of CH_3NH_3^+ will be:

CH_3NH_3^+(aq)\rightleftharpoons H^+(aq)+CH_3NH_2(aq)

The equilibrium expression :

K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

(A) The dissociation reaction of HC_2H_3O_2 will be:

HC_2H_3O_2(aq)\rightleftharpoons H^+(aq)+C_2H_3O_2^-(aq)

The equilibrium expression of HC_2H_3O_2 will be:

K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}

(B) The dissociation reaction of Co(H_2O)_6^{3+} will be:

Co(H_2O)_6^{3+}(aq)\rightleftharpoons H^+(aq)+Co(H_2O)_5(OH)^{2+}(aq)

The equilibrium expression of Co(H_2O)_6^{3+} will be:

K_a=\frac{[H^+][Co(H_2O)_5(OH)^{2+}]}{[Co(H_2O)_6^{3+}]}

(C) The dissociation reaction of CH_3NH_3^+ will be:

CH_3NH_3^+(aq)\rightleftharpoons H^+(aq)+CH_3NH_2(aq)

The equilibrium expression of CH_3NH_3^+ will be:

K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}

3 0
3 years ago
According to the balanced equation shown below, 1.00 mole of oxalic acid, h2c2o4, reacts with _________ moles of permanganate io
zheka24 [161]
The balanced equation that shows the reaction between oxalic acid and permanganate ion in an acidic medium is: 2MnO4- + 5H2C2O4 + 6H+ -> 2Mn(2+) + 10CO2 + 8H2O. Thus, 1 mole of oxalic acid reacts with 0.4 mole of permanganate ion. This was obtained using stoichiometry:

1 mol H2C2O4 x (2 mol MnO4-/ 5 mol H2C2O4) = 0.4 mol MnO4- 

In this redox reaction, the permanganate is reduced to manganese(II) ion.
6 0
3 years ago
In which state of H2O will the molecule have the highest kinetic energy? *
kipiarov [429]
The answer is Steam because gas has the most motion
8 0
3 years ago
Read 2 more answers
Replacing standard incandescent light bulbs with energy-efficient compact fluorescent lightbulbs can save a lot of energy. Calcu
EleoNora [17]

Answer:

a) 1512000 Joules

b) 5040 seconds = 84 minutes = 1.4 hours

Explanation:

Power saved y replacing bulbs = 60-18 = 42 W = 42 J/s

Time the bulb is used for = 10 hours

Energy saved during this time

42×10×60×60 = 1512000 Joules

Saved energy by replacing standard incandescent lightbulbs with energy-efficient compact fluorescent lightbulbs in 10 hours is 1512000 Joules

b) Power the plasma TV uses = 300 W = J/s

\frac{1512000}{300}=5040\ s3001512000=5040 s

Time a plasma TV can be used for with the saved energy is 5040 seconds = 84 minutes = 1.4 hours.

3 0
3 years ago
Other questions:
  • Which type of bonding involves the complete transfer of a valence electron from a less electronegative atom to a more electroneg
    13·2 answers
  • At constant volume, the heat of combustion of a particular compound, compound A, is − 3039.0 kJ / mol. When 1.697 g of compound
    11·1 answer
  • One reaction involved in the conversion of iron ore to the metal is FeO(s) + CO(g) → Fe(s) + CO2(g) Use Hess’s Law to calculate
    15·1 answer
  • how many grams of nahco3 (fm84.007) must be added ro 4.00g of k2co3 (fm 138.206) to give a ph of 10.80 in 500ml of water​
    10·1 answer
  • HELP PLEASE!!!! Identify the position of each chemical family on the periodic table
    5·1 answer
  • Lipid bilayers:A. depend on hydrophobic interactions to arrange the polar head groups together in the interior of the bilayer. B
    14·1 answer
  • At 25°C, gas in a rigid cylinder with a movable piston has a volume of 145 mL and a pressure of 125 kPa. Then the gas is compres
    15·1 answer
  • Where do an organisms genes come from?
    9·1 answer
  • What physical properties does radium have
    5·1 answer
  • Name 3 places that are carbon reservoirs​
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!