All categories

3 years ago

Which metal does not form cations of differing charges? ( Which metal is NOT a transition metal?)

Chemistry

1 answer:

vitfil [10]3 years ago

3 0

Answer:Na

Explanation:its not in group 3 to 13 hope this helps god bless

You might be interested in

When H2SO4 is added to PbI2, a precipitate of PbSO4 forms. The PbSO4 is then filtered from the solution, dried, and weighed. If

Nookie1986 [14]

Answer:

$n_{I^-}=3.11x10^{-4}molI^-$

Explanation:

Hello,

In this case, the undergoing chemical reaction is shown below:

$H_2SO_4(aq)+PbI_2(aq)\rightarrow PbSO_4(s)+2HI(aq)$

Thus, we obtain 0.0471 g of lead (II) sulfate, the iodide ions in the original solution are computed below by stoichiometry, taking into account that into 1 mole of lead (II) iodide there are 2 moles of iodide ions:

$n_{I^-}=0.0471gPbSO_4*\frac{1molPbSO_4}{303.26gPbSO_4}*\frac{1molPbI_2}{1molPbSO_4}*\frac{2molI^-}{1molPbI_2} \\n_{I^-}=3.11x10^{-4}molI^-$

Best regards.

3 0

3 years ago

A catalyst is:

icang [17]

A catalyst is a substance that increases the rate of a chemical reaction without itself being consumed . (ans: second choice)

7 0

2 years ago

Read 2 more answers

List 5 spheres and give an example of something you would find in each sphere . Ill give 50 points

Brilliant_brown [7]

Hydrosphere, atmosphere, geosphere, biosphere, anthrosphere.

Hydrosphere: Liquid, vapour or ice.

Atmosphere: Oxygen.

Geosphere: Minerals.

Biosphere: Ecosystem.

Anthrosphere: Human habitats

3 0

2 years ago

Read 2 more answers

As a temperature of Lava increases, ___________.

levacccp [35]

B its viscosity decreases

3 0

3 years ago

Read 2 more answers

A 155.0 g piece of copper at 128 oC is dropped into 250.0 g of water at 17.9 oC. (The specific heat of copper is 0.385 J/goC.) C

Mamont248 [21]

Answer:

$T_{eq}=23.85^oC$

Explanation:

Hello,

In this case, as the copper's heat loss is gained by the water, the following energetic relationship is:

$\Delta H_{Cu}=-\Delta H_{H_2O}$

Therefore the equilibrium temperature shows up as:

$m_{Cu}Cp_{Cu}(T_{Cu}-T{eq}) = m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})\\\\T_{eq}=\frac{m_{Cu}Cp_{Cu}T_{Cu}-m_{H_2O}Cp_{H_2O}T_{H_2O}}{m_{Cu}Cp_{Cu}-m_{H_2O}Cp_{H_2O}} \\$

Thus, by knowing that water's heat capacity is 4.18J/g°C, one obtains:

$T_{eq}=\frac{155.0g*0.385\frac{J}{g^oC}*128^oC+250.0g*4.18\frac{J}{g^oC}*17.9^oC}{155.0g*0.385\frac{J}{g^oC}+250.0g*4.18\frac{J}{g^oC}}=23.85^oC$

Best regards.

6 0

3 years ago

Read 2 more answers