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Vlad [161]
4 years ago
11

The chef has 25% pounds of loin strip. The trim loss on the strip loin is 35% and the cooking loss is 80% of the trimmed weight.

How many pounds of trimmed, cooked strip loin will the chef have left to serve to has customers?
Mathematics
1 answer:
USPshnik [31]4 years ago
8 0

Answer:

3.25 pounds

Step-by-step explanation:

Starting with 25 pounds we trim off 35%:

25 X .35 = 8.75 trimmed off

This leaves 25 - 8.75 pounds of trimmed meat:

25 - 8.75 = 16.25 of trimmed meat.

During cooking we lose another 80% of the weight of the meat:

16.25 X .80 = 13 pounds "cooked off"

So the remaining weight of meat is 16.25 - 13:

16.25 - 13 = 3.25 pounds of trimmed cooked meat.

How sad is that?

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x=\frac{7}{5} \\
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x-2y=-1 \\
\frac{7}{5}-2y=-1 \\
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y=\frac{6}{5} \\
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2.
x+3y=4 \ \ \ |\times 2 \\
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3.
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4.
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3 0
3 years ago
The ___ two sets is the set of elements but could be found in both sets at the same time
Zanzabum

Answer:

The answer is

Intersection

Hope this helps

7 0
4 years ago
What is the inverse of the function f(x) = 2x – 10? A. h(x) = 2x - 5
Licemer1 [7]

Answer:

f^-1(x)=1/2x+5

Step-by-step explanation:

y=2x-10

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x=2y-10

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divide by 2both sides

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4 0
3 years ago
The mass (m grams) of a bar of gold is directly proportional to its volume (V cm3)
Anni [7]

Answer:

The volume of a bar of gold with a mass of 66.5 grams is  3.5cm^{3}

Step-by-step explanation:

Given ,  mass(in grams)  ∝ Volume (in cm3)

Here, volume of  95 grams bar = 5cm3

So, thevolume of 1 gram bar = \frac{5 cm^{3} }{95 g}  = \frac{1}{19}  cm^{3}

⇒The volume of  a bar with weight 66.5 grams =  \frac{1}{19}  \times 66.5 =  3.5 cm^{3}

So, the volume of a bar of gold with a mass of 66.5 grams is  3.5cm^{3}

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Dividing the number by 1,000 is the same as moving the decimal point left 3 points.
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