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3 years ago

The mass (m grams) of a bar of gold is directly proportional to its volume (V cm3)

Mathematics

1 answer:

Anni [7]3 years ago

7 0

Answer:

The volume of a bar of gold with a mass of 66.5 grams is $3.5cm^{3}$

Step-by-step explanation:

Given , mass(in grams) ∝ Volume (in cm3)

Here, volume of 95 grams bar = 5cm3

So, thevolume of 1 gram bar = $\frac{5 cm^{3} }{95 g}$ = $\frac{1}{19} cm^{3}$

⇒The volume of a bar with weight 66.5 grams = $\frac{1}{19} \times 66.5 = 3.5 cm^{3}$

So, the volume of a bar of gold with a mass of 66.5 grams is $3.5cm^{3}$

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Step-by-step explanation:

STEP 1

Writing out the equation to represent if 7 cups of apples make 4 batches One batch is as a result of how many cups of apples

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2 years ago

What is the answer to this problem 0.05n+0.10(2n)=9.25

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2 years ago

the eccentricity of a hyperbola is defined as e=c/a. find an equation with vertices (1,-3) and (-3,-3) and e=5/2

Ksivusya [100]

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Step-by-step explanation:

If (α, β) are the coordinates of the center of the hyperbola, then its equation of the hyperbola is $\frac{(x - \alpha )^{2} }{a^{2} } - \frac{(y - \beta )^{2} }{b^{2} } = 1$ .

Now, the vertices of the hyperbola are given by (α ± a, β) ≡ (1,-3) and (-3,-3)

Hence, β = - 3 and α + a = 1 and α - a = -3

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