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3 years ago

The mass (m grams) of a bar of gold is directly proportional to its volume (V cm3)

Mathematics

1 answer:

Anni [7]3 years ago

7 0

Answer:

The volume of a bar of gold with a mass of 66.5 grams is $3.5cm^{3}$

Step-by-step explanation:

Given , mass(in grams) ∝ Volume (in cm3)

Here, volume of 95 grams bar = 5cm3

So, thevolume of 1 gram bar = $\frac{5 cm^{3} }{95 g}$ = $\frac{1}{19} cm^{3}$

⇒The volume of a bar with weight 66.5 grams = $\frac{1}{19} \times 66.5 = 3.5 cm^{3}$

So, the volume of a bar of gold with a mass of 66.5 grams is $3.5cm^{3}$

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Find the value of Y<br> .....

vekshin1

Answer:

$y = 6 \sqrt{3} \: units$

Step-by-step explanation:

In order to find the value of y, first we need to find the length of the perpendicular dropped from one of the vertices of the triangle to its opposite side.

By geometric mean theorem:

Length of the perpendicular

$=\sqrt{9\times 3}$

$=\sqrt{27}\: units$

Next, by Pythagoras theorem:

${y}^{2} = {9}^{2} + {( \sqrt{27} )}^{2} \\ \\ {y}^{2} = 81 + 27 \\ \\ {y}^{2} = 108 \\ \\ y = \sqrt{108} \\ \\ y = \sqrt{36 \times 3} \\ \\ y = \sqrt{ {6}^{2} \times 3} \\ \\ y = 6 \sqrt{3} \: units$

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2 years ago

Solve for x: −2(x + 3) = −2(x + 1) − 4. (1 point) a 2 b 3 c All real numbers d No solution

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-2(x + 3) = -2(x + 1) - 4

-2x - 6 = -2x - 2 - 4 <em>distributed -2 on the left and on the right</em>

-2x - 6 = -2x - 6

-6 = -6

TRUE

Since this is a true statement, there are infinite solutions (aka All Real Numbers)

Answer: C

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3 years ago

Megan is making bracelets to sell to earn money for the local animal shelter. It takes her 1/4 hour to pick out all the beads an

nalin [4]

1/4 + 1/10 = 5/20 + 2/20 = 7/20 = 0.35

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3 years ago

I need help on these two questions

Ray Of Light [21]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

pogonyaev

By using the general equation for a circle, we will see that the correct options are:

1) This is a circle centered at (-3, - 5) with a radius of 4 units.
2) The center is (-3, 5) and the radius is 2 units.
3) The center is (3, 5) and the radius is 2 units.
4) This is a circle centered at (3, - 5) with a radius of 4 units.

<h3>How to write a circle equation?</h3>

For a circle of radius R and center (a, b), the equation is given by:

(x - a)^2 + (y - b)^2 = R^2

With that in mind, if we look at the first equation:

(x + 3)^2 + (y + 5)^2 = 16 = 4^2

This is a circle centered at (-3, - 5) with a radius of 4 units.

For the second equation:

(x + 3)^2 + (y - 5)^2 = 4 = 2^2

The center is (-3, 5) and the radius is 2 units.

The third equation is:

(x - 3)^2 + (y - 5)^2 = 4 = 2^2

The center is (3, 5) and the radius is 2 units.

The fourth equation is:

(x - 3)^2 + (y + 5)^2 = 16 = 4^2

This is a circle centered at (3, - 5) with a radius of 4 units.

If you want to learn more about circles, you can read:

brainly.com/question/14283575

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2 years ago